Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 24, Problem 26QLP
What similarities and differences are there in slitting with a milling cutter and with a saw?
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Following are the data in an orthogonal cutting
operation.
Rake angle = 15°
Cutting speed = 20 m/min
Chip thickness = 0.7 mm
Width of cut = 4.5 mm
Cutting ratio = 0.714
Assuming Merchant's theory, coefficient of friction at
the tool-chip interface is
.cutting speed is 9m/min. The return time to cutting time is 1:4 and the feed is 3mm
Q.4 (i)
Find the time required for taking a cemplete cut on a plate 600 × 900 mm", if the
cutting speed is 9m/min. The return time to cutting time is 1:4 and the feed is 3mm
for the shaper. The clearance at each end is 75 mm.
(11) A hole of 30 mm diameter and 75 mm depth is to be drilled. The feed is 1.3
mm/rev and the cutting speed is 62 m/min. Assuming tool approach and tool over
travel as 6 mm. Calculate :
(a) Cutting time and
(b) Material removal rate
Q.5 Write short note on the following -
(i) Up milling and down milling processes
(ii) Balancing of grinding wheels
(iii) Gear hobbing
ittp3.7 w w w.ItuommC.com
Rake angle=20 degree, Depth of cut=6 mm, Feed rate =0.25mm/rev,Cutting speed=0.6 m/s, chip length before cutting=29.4mm, vertical cutting force= 1050 NHorizontal cutting force=630, chip length after cutting=12.9Using Merchant’s analysis calculate(a) direction and magnitude of resultant force(b) friction force and friction angle(c) shear plane angle
Chapter 24 Solutions
Manufacturing Engineering & Technology
Ch. 24 - Explain why milling is such a versatile machining...Ch. 24 - Describe a milling machine. How is it different...Ch. 24 - Describe the different types of cutters used in...Ch. 24 - Define the following: face milling, peripheral...Ch. 24 - Can threads be machined on a mill? Explain.Ch. 24 - What is the difference between feed and feed per...Ch. 24 - Explain the relative characteristics of climb...Ch. 24 - Describe the geometric features of a broach and...Ch. 24 - What is a pull broach? A push broach?Ch. 24 - Why is sawing a commonly used process? Why do some...
Ch. 24 - What advantages do bed-type milling machines have...Ch. 24 - Explain why the axis of a hob is tilted with...Ch. 24 - What is a shell mill? Why is it used?Ch. 24 - Why is it difficult to saw thin sheet metals?Ch. 24 - Of the processes depicted in Fig. 24.2, which is...Ch. 24 - Describe the tool motion during gear shaping.Ch. 24 - When is filing necessary?Ch. 24 - Would you consider the machining processes...Ch. 24 - Why is end milling such an important versatile...Ch. 24 - List and explain factors that contribute to poor...Ch. 24 - Explain why broaching crankshaft bearings is an...Ch. 24 - Several guidelines are presented in this chapter...Ch. 24 - What are the advantages of helical teeth over...Ch. 24 - Explain why hacksaws are not as productive as band...Ch. 24 - What similarities and differences are there in...Ch. 24 - Why do machined gears have to be subjected to...Ch. 24 - How would you reduce the surface roughness shown...Ch. 24 - Why are machines such as the one shown in Fig....Ch. 24 - Comment on your observations concerning the...Ch. 24 - Explain how contour cutting could be started in a...Ch. 24 - Prob. 32QLPCh. 24 - Describe the parts and conditions under which...Ch. 24 - Explain the reason that it is difficult to use...Ch. 24 - Would you recommend broaching a keyway on a gear...Ch. 24 - Prob. 37QTPCh. 24 - A slab-milling operation is being performed at a...Ch. 24 - Show that the distance lc in slab milling is...Ch. 24 - Prob. 40QTPCh. 24 - Calculate the chip depth of cut, tc, and the...Ch. 24 - Estimate the time required to face mill a...Ch. 24 - A 12-in.-long, 1-in.-thick plate is being cut on a...Ch. 24 - A single-thread hob is used to cut 40 teeth on a...Ch. 24 - Assume that m the face-milling operation shown in...Ch. 24 - A slab-milling operation will take place on a part...Ch. 24 - Prob. 47QTPCh. 24 - In describing the broaching operations and the...Ch. 24 - The parts shown in Fig. 24.1 are to be machined...Ch. 24 - Would you prefer to machine the part in Fig. 24....Ch. 24 - Prob. 51SDPCh. 24 - Suggest methods whereby milling cutters of various...Ch. 24 - Prepare a comprehensive table of the process...Ch. 24 - Prob. 55SDPCh. 24 - Make a list of all the processes that can be used...
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- (d) List down three types of milling cutters used in machining process and sketch their cutting process. (e) Find the cutting speed of a 15 mm diameter bar being turned with a spindle of 955 rev/min.arrow_forwardExamples (homework) 1. In orthogonal cutting if the depth of cut is a 1.25 mm and chip thickness after cutting is 2 mm, determine the following: i.Chip thickness ratio. ii.Shear angle. If rake angle is 10. 2. If shear strength is 6000 kg/cm2, width of cut is 10mm, cutting speed is 30 m/min, coefficient of friction is 0.9 Determine the following: i.Shearing force. •Friction angle. •Cutting force.arrow_forward12. A 600 mm × 30 mm flat surface of a plate is to be finish machined on a shaper. The plate has been fixed with the 600 mm side along the tool travel direction. If the tool over-travel at each end of the plate is 20 mm, average cutting speed is 8 m/min, feed rate is 0.3 mm/stroke and the ratio of return time to cutting time of the tool is 1:2, the time required for machining will be (a) 8 minutes (b) 12 minutes (c) 16 minutes (d) 20 minutesarrow_forward
- please answer with detail explanation.arrow_forwardConsider a profile milling operation, where the initial (stock) geometry has (X,Y,Z) dimensions of 100 mm x 75 mm x 50 mm. The target part has dimensions of 95 mm x 70 mm x 50 mm. The target part is located in the centre of the stock part, i.e. the stock to be removed from all sides is equal. The operation has a cutting time of 1 minute. The tool axis is along the Z direction and the tool diameter is 12 mm having 6 cutting edges. The takes place at 54m/min feed rate of 0.2 mm/rev/tooth. Calculate the axial depth of cut ? process at aarrow_forwardA 600mm*30mm flat surface of a plate is to be finish machined on a shaper .The plate has been fixed with 600 mm side along the tool travel direction. If the tool over-travel at each end of the plate is 20 mm, average cutting speed is 8 m/min, feed rate is 0.3 mm/stroke and the ratio of return time to cutting time of the tool is 1:2 Determine time required for machining?arrow_forward
- A flat milling operation will be carried out with a horizontal milling machine, in a piece of 250 mm in length and 50 mm in width, using a felicoidal bur with a diameter of 75 mm, with 10 teeth. If the feed per tooth is 0.2mm, and the cutting speed is 0.75 m / s, how would you determine the speed of metal removal to remove 6 mm from the surface of this piece?arrow_forwardi need the answer quicklyarrow_forwardThe following data is given for slab milling of a 300 mm long 50 mm wide mild steel block: Cutter of diameter= 60 mm; Numbers of teeth =12; Cutter speed = 120 rev/min; Depth of cut = 3.2 mm; Feed is 0.25 mm/tooth.Determine (i) Table feed in mm/min, (ii) MRR (iii) Power (iv) Torque and (v) Total machining time. Assumesuitable approach and over-run and specific energy of mild steel as 5 Ws/mm3.arrow_forward
- Assume that, in orthogonal cutting, the rake angle is 20 and the friction angle is 35 at thechip-tool interface. Determine the percentage change in chip thickness when the frictionangle is 50. Note that Merchant’s equation is more preferable.arrow_forwardThe orthogonal cutting of steel is done with 10° rake tool with a depth of cut of 4mm feed rate of 0.4mm/rev. The cutting speed is 200m/min. The chip thickness ratio is 0.35. The vertical cutting force is 1200N and the horizontal cutting force is 700N. Calculate from the Merchant's theory, the various work done in metal cutting and shear stress.arrow_forwardIn orthogonal cutting, __________ are independent variables. I. Surface finish of cutting tool;II. Temperature rise in workpiece;III. Depth of cut;IV. Tool holder;V. Cutting force;VI. Stiffness of cutting toolarrow_forward
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