Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 24, Problem 17P
To determine

The full angular width of central diffraction peak.

Expert Solution & Answer
Check Mark

Answer to Problem 17P

  1.51° .

Explanation of Solution

Given:

Width of slit, d=0.0440mm=0.000044m

Order, m=1

Wavelength, λ=580nm=580×109m

Formula used:

It is known that sinθ=mλd

Where,

  m is an integer

  λ is wavelength

  d is a distance

Calculation:

Rearrange the given formula,

  sinθ=mλd

So,

  θ=sin1mλd

The path difference is an integer multiple of the wavelength in constructive interference.

Substitute the given values in formula,

  θ1min=sin1mλd

  θ1min=sin1580×1090.000044=0.755°

It is known that width =2θ

Now, calculate the angular width of the central diffraction

  Δθ1=2θ1min

  =0.755°×2=1.51°

Conclusion:

The required angle is 1.51° .

Chapter 24 Solutions

Physics: Principles with Applications

Ch. 24 - Prob. 11QCh. 24 - Prob. 12QCh. 24 - Prob. 13QCh. 24 - Prob. 14QCh. 24 - Prob. 15QCh. 24 - Prob. 16QCh. 24 - Prob. 17QCh. 24 - Prob. 18QCh. 24 - Prob. 19QCh. 24 - Prob. 20QCh. 24 - Prob. 21QCh. 24 - Prob. 22QCh. 24 - Prob. 23QCh. 24 - Prob. 24QCh. 24 - Prob. 25QCh. 24 - Prob. 26QCh. 24 - Prob. 27QCh. 24 - Prob. 28QCh. 24 - Prob. 29QCh. 24 - Prob. 30QCh. 24 - Prob. 31QCh. 24 - Prob. 32QCh. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6PCh. 24 - Prob. 7PCh. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10PCh. 24 - Prob. 11PCh. 24 - Prob. 12PCh. 24 - Prob. 13PCh. 24 - Prob. 14PCh. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 23PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 30PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Prob. 36PCh. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Prob. 41PCh. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45PCh. 24 - Prob. 46PCh. 24 - Prob. 47PCh. 24 - Prob. 48PCh. 24 - Prob. 49PCh. 24 - Prob. 50PCh. 24 - Prob. 51PCh. 24 - Prob. 52PCh. 24 - Prob. 53PCh. 24 - Prob. 54PCh. 24 - Prob. 55PCh. 24 - Prob. 56PCh. 24 - Prob. 57PCh. 24 - Prob. 58PCh. 24 - Prob. 59PCh. 24 - Prob. 60PCh. 24 - Prob. 61PCh. 24 - Prob. 62GPCh. 24 - Prob. 63GPCh. 24 - Prob. 64GPCh. 24 - Prob. 65GPCh. 24 - Prob. 66GPCh. 24 - Prob. 67GPCh. 24 - Prob. 68GPCh. 24 - Prob. 69GPCh. 24 - Prob. 70GPCh. 24 - Prob. 71GPCh. 24 - Prob. 72GPCh. 24 - Prob. 73GPCh. 24 - Prob. 74GPCh. 24 - Prob. 75GPCh. 24 - Prob. 76GPCh. 24 - Prob. 77GPCh. 24 - Prob. 78GPCh. 24 - Prob. 79GPCh. 24 - Prob. 80GPCh. 24 - Prob. 81GPCh. 24 - Prob. 82GPCh. 24 - Prob. 83GPCh. 24 - Prob. 84GPCh. 24 - Prob. 85GPCh. 24 - Prob. 86GPCh. 24 - Prob. 87GPCh. 24 - Prob. 88GP
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