Chapter 23.5, Problem 8Q

Interpretation Introduction

Interpretation: The volume of NaOH has to be calculated for the reaction between BPA and $0.050\text{ M}$ NaOH.

Concept introduction:

The reaction between NaOH and BPA is a weak acid vs strong base titration. BPA has two hydroxyl groups which will be neutralized by NaOH. The volume of NaOH is calculated by using following expression,

${\text{M}}_{\text{1}}{\text{V}}_{\text{1}}{\text{ = M}}_{\text{2}}{\text{V}}_{\text{2}}$ (1)

Here, ${\text{M}}_{\text{1}}$ and ${\text{M}}_{\text{2}}$ are concentration values of acid and base respectively. And ${\text{V}}_{\text{1}}$ and ${\text{V}}_{\text{2}}$ are volume of acid and base respectively.

$\text{Molarity}=\frac{\text{mass}}{\left(\text{molar mass}\right)\left(1\text{ L volume of solvent}\right)}\text{M}$