EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 23, Problem 41QTP
Calculate the same quantities as in Example 23.1 for high-strength titanium alloy and at N = 700 rpm.
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Chapter 23 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 23 - Describe the types of machining operations that...Ch. 23 - What is turning? What kind of chips are produced...Ch. 23 - What is the thrust force in turning? What is the...Ch. 23 - What are the components of a lathe?Ch. 23 - (a) What is a tracer lathe? (b) What is an...Ch. 23 - Describe the operations that can be performed on a...Ch. 23 - Why were power chucks developed?Ch. 23 - Explain why operations such as boring on a lathe...Ch. 23 - Why are turret lathes typically equipped with more...Ch. 23 - Describe the differences between boring a...
Ch. 23 - How is drill life determined?Ch. 23 - What is the difference between a conventional...Ch. 23 - Why are reaming operations performed?Ch. 23 - Explain the functions of the saddle on a lathe.Ch. 23 - Describe the relative advantages of (a)...Ch. 23 - Explain how external threads are cut on a lathe.Ch. 23 - Prob. 17RQCh. 23 - Explain the reasoning behind the various design...Ch. 23 - Note that both the terms tool strength and...Ch. 23 - (a) List and explain the factors that contribute...Ch. 23 - Explain why the sequence of drilling, boring, and...Ch. 23 - Why would machining operations be necessary even...Ch. 23 - A highly oxidized and uneven round bar is being...Ch. 23 - Describe the difficulties that may be encountered...Ch. 23 - (a) Does the force or torque in drilling change as...Ch. 23 - Explain the similarities and differences in the...Ch. 23 - Describe the advantages and applications of having...Ch. 23 - Assume that you are asked to perform a boring...Ch. 23 - Explain the reasons for the major trend that has...Ch. 23 - Describe your observations concerning the contents...Ch. 23 - The footnote to Table 23.12 states that as the...Ch. 23 - In modern manufacturing, which types of metal...Ch. 23 - Sketch the tooling marks you would expect if a...Ch. 23 - What concerns would you have in turning a powder...Ch. 23 - The operational severity for reaming is much lower...Ch. 23 - Review Fig. 23.6, and comment on the factors...Ch. 23 - Explain how gun drills remain centered during...Ch. 23 - Comment on the magnitude of the wedge angle on the...Ch. 23 - If inserts are used in a drill bit (see Fig....Ch. 23 - Refer to Fig. 23.11b, and in addition to the tools...Ch. 23 - Calculate the same quantities as in Example 23.1...Ch. 23 - Estimate the machining time required to rough turn...Ch. 23 - A high-strength cast-iron bar 8 in. in diameter is...Ch. 23 - A 0.30-in.-diameter drill is used on a drill press...Ch. 23 - In Example 23.4, assume that the workpiece...Ch. 23 - For the data in Problem 23.45, calculate the power...Ch. 23 - A 6-in.-diameter aluminum cylinder 10 in. in...Ch. 23 - A lathe is set up to machine a taper on a bar...Ch. 23 - Assuming that the coefficient of friction is 0.25,...Ch. 23 - A 3-in.-diameter, gray cast iron cylindrical part...Ch. 23 - Would you consider the machining processes...Ch. 23 - Would it be difficult to use the machining...Ch. 23 - If a bolt breaks in a hole, it typically is...Ch. 23 - An important trend in machining operations is the...Ch. 23 - Review Fig. 23.8d, and explain if it would be...Ch. 23 - Boring bars can be designed with internal damping...Ch. 23 - A large bolt is to be produced from extruded...Ch. 23 - Make a comprehensive table of the process...
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- A 200 mm long magnesium alloy bar, 63 mm in diameter is turned on a lathe using a high speed steel cutter travelling at 180 mm/min. The spindle rotates at 450 rpm and lathe is equipped with a 10 kW motor, operating at a mechanical efficiency of 92%. The final diameter of the magnesium alloy bar is 59,5 mm. Indicate with a sketch the recommend size and location of the following tool angles: back rake, side rake, end relief, side relief and side and end cutting edge. Calculate the cutting time for the machining process.Calculate the required cutting force.arrow_forward1. A 7.5 -mm-diameter drill is used on a drill press operating at 300 rpm. If the feed is 0.125 mm/rev, what is the MRR? What is the MRR if the drill diameter is doubled? 2. Assume that the work piece material is high-strength aluminum alloy and the spindle is running at N = 500 rpm. Estimate the torque required for this operation.arrow_forwardA 150-mm-long, 10-mm-diameter, high-strength cast iron rod is being reduced in diameter to 8 mm by turning on a lathe. The spindle rotates at N = 500 rpm., and the tool is traveling at an axial speed of 200 mm/min.arrow_forward
- Explain the properties and applications of High Speed Steelarrow_forwardIn a straight turning operations the diameter of a workpiece is reduced from 50 mm 40 mm using a feed rate of 0.1 mm/rev. The cutting tool used for the process has a normal working rake angle of 15°, clearance angle of 4° and a lead angle of 90°. The cutting force of 1200N and a thrust force of 660 N is measured during cutting operations. The workpiece material was stainless steel with a density of 7850 Kg/m³, thermal conductivity is 15 J/smK, specific heat is 480 J/kgK. The width of the secondary deformation zone divided by the chip thickness wo is assumed to be 0.2 for the above mentioned cutting conditions. The chip/tool contact length is measured as 1.5 mm. (a) Calculate the temperature rise in the primary deformation zone (b) Calculate the temperature rise in the secondary deformation zone (c) Calculate the maximum temperature if the room temperature is 24°C If the tool life for the average cutting velocity of 90 m/min is measured as 10 min. and for a cutting velocity of 160 m/min…arrow_forwardPlease solve question 2,3 and 13. Determine the % change in the machine time for an USM operation cutting WC plate when the tool material is changed from copper to stainless steel. Take ratio of flow stress of WC to flow stress of copper is 4.6 and the ratio of flow stress of WC to the flow stress of SST is 1.2.arrow_forward
- Please solve it on neat paper.arrow_forwardA mild steel block is being drilled with a drill of 10 mm diameters. Given Helix angle = 30° Feed = 0.2 mm/rev %3D Ts = 450 N/mm? Estimate the drilling torque and thrust using Lee and Shaffer's shear angle relation. Assume the coefficient of friction between the chip and the drill to be 0.75.arrow_forwardDefine specific energy for plane strain machining (cutting). In plane-strain machỉning, the two main sources of energy dissipation are deformation along the shear plane (~70%) and friction at the tool-chip contact along the rake face (~30%). Consider machining of a rigid perfectly-plastic work material whose uniaxial yield stress is 700 MPa, and is independent of strain rate and temperature. A tool of zero-degree rake angle is employed. Measurements showed the (deformed) chip thickness to be twice that of the undeformed chip thickness. Based on the aforementioned distribution of energy, estimate the specific energy for this process.arrow_forward
- A high-speed steel tool is used to turn a steel work part that is 360 mm long and 78 mm in diameter. The parameters in the Tylor equation are: n = 0.12 and C = 71 m/min for a feed of 0.40 mm/rev. The operator and machine tool rate = $36.00/hr, and the tooling cost per cutting edge = $4.25. It takes 3.5 min to load and unload the work part and 5.0 min to change tools. The total time required to produce one unit is closest to, A high-sneed stel tool is ucod to tuurnarrow_forwardHi, could you show workings out if possible please, thanks youarrow_forwardA slab-milling operation is carried out on a 200 mm long, 80-mm-wide annealed mild-steel workpiece having a feedrate of 0.1 mm/tooth and a depth of cut of 4.0 mm. The cutter of 50 mm diameter has 18 straight teeth and rotates at 135 rpm. The given specific energy for this material is 3.5 W s/mm3 and the slab mill is wider than the workpiece to be machined. Calculate:‧ the material-removal rate;‧ the power and torque required for this operation;‧ the cutting time. (243 mm/min, 77760 mm3/min, 4.5 kW, 52.8 s)arrow_forward
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