EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
3rd Edition
ISBN: 9781259298424
Author: SMITH
Publisher: VST
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Chapter 23, Problem 23.73P
Interpretation Introduction

Interpretation:

The role of creatine phosphate which is stored in muscles needs to be determined.

Concept introduction:

A biochemical reaction refers to a chemical reaction in which one molecule is transformed into different molecules present inside the cell of the living beings. When glucose enters the cell, it gets broken down to form ATP. This process occurs in the process known as the citric acid cycle which takes place in the mitochondrion of the cell.

Mitochondrion refers to a small organelle that is placed in the cytoplasm of the cell.

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A student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ ப
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Shown below are five NMR spectra for five different C6H10O2 compounds.  For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm).  IR information is also provided.  As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1

Chapter 23 Solutions

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM

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