Chapter 2.3, Problem 129E

[T] In physics, the magnitude of an electric field generated by a point charge at a distance r in vacuum is governed by Coulomb’s law: $E\left(r\right)=\frac{q}{4\pi {\epsilon }_0{r}^2}$ , where E represents the magnitude of the electric field, q is the charge of the particle, r is the distance between the particle and where the strength of the field is measured, and $\frac{1}{4\pi {\epsilon }_0}$ is Coulomb's constant: $8.988\times {10}^{9}N\cdot m^2/C^2$ .

1. Use a graphing calculator to graph E(r) given that
the charge of the panicle is $q={10}^{-10}$ .

Evaluate $\underset{r\to 0^{+}}{\lim }E\left(r\right)$. What is the physical meaning of this quantity⁷? Is it physically relevant? Why are you evaluating from the right?