EBK ORGANIC CHEMISTRY-PRINT COMPANION (
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Chapter 22, Problem 81IP
Interpretation Introduction

Interpretation: The structure of coniine has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions.  This reaction is called Hofmann elimination.  The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group.  After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes.  Alkene formation involves in E2 elimination.  Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

EBK ORGANIC CHEMISTRY-PRINT COMPANION (, Chapter 22, Problem 81IP

To find: The structure of coniine via Hofmann elimination

Identify the nature of unsaturation in coniine

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Feedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a X
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1. Identify the following alkenes as E or Z NH₂ Br 2. Draw the structures based on the IUPAC names (3R,4R)-3-bromo-4-fluoro- 1-hexene (Z)-4-bromo-2-iodo-3-ethyl- 3-heptene تر 3. For the following, predict all possible elimination product(s) and circle the major product. HO H₂SO4 Heat 80 F4 OH H2SO4 Heat 어요 F5 F6 1 A DII 4 F7 F8 F9 % & 5 6 7 * ∞ 8 BAB 3 E R T Y U 9 F D G H J K O A F11 F10

Chapter 22 Solutions

EBK ORGANIC CHEMISTRY-PRINT COMPANION (

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