(a)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If ,
and
groups are attached to the parent carbon, they are called primary, secondary and tertiary
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
(b)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If ,
and
groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
In the given compound (b), three alkyl groups are attached to nitrogen atom. Therefore, it belongs to tertiary amine.
Decide the given name which is in general name method or IUPAC name method
There are three alkyl groups present in the given name. Here, the main chain is cyclopropylamine. Three-membered carbon ring structure is called cyclopropyl group. So, general name system is followed.
Locate the substituents and draw the corresponding structure for the given name
(c)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If ,
and
groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
In the given compound (c), only one alkyl group, namely pentane is attached to nitrogen atom. Therefore, it belongs to primary amine.
Decide the given name which is in general name method or IUPAC name method
There is only one alkane group present in the given name. It is pentane attached to primary amine named as pentanamine which is the main chain of the given name. So, IUPAC name system is followed.
Locate the substituents and draw the corresponding structure for the given name
(d)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If ,
and
groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
In the given compound (d), only one alkyl group is attached to nitrogen atom. Therefore, it belongs to primary amine.
Decide the given name which is in general name method or IUPAC name method
There is only one alkyl group present in the given name. It is benzyl group. So, simple general name system is followed. If phenyl group is attached to methylene group, it is called benzyl group.
Locate the substituents and draw the corresponding structure for the given name
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Chapter 22 Solutions
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
- Please answer 1, 2 and 3 on the endarrow_forwardIn the box below, specify which of the given compounds are very soluble in polar aprotic solvents. You may select more than one compound. Choose one or more: NaCl NH4Cl CH3CH2CH2CH2CH2CN CH3CH2OH hexan-2-one NaOH CH3SCH3arrow_forwardOn the following structure, select all of the atoms that could ACCEPT a hydrogen bond. Ignore possible complications of aromaticity. When selecting be sure to click on the center of the atom.arrow_forward
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- The reaction: 2NO2(g) ⇌ N2O4(g) is an exothermic reaction, ΔH=-58.0 kJ/molrxn at 0°C the KP is 58.If the initial partial pressures of both NO2(g) and N2O4(g) are 2.00 atm:A) Is the reaction at equilibrium? If not, what is the value of Q? B) Which direction will the reaction go to reach equilibrium? C) Use an ICE table to find the equilibrium pressures.arrow_forwardThe dissociation of the weak acid, nitrous acid, HNO2, takes place according to the reaction: HNO2 (aq) ⇌ H+(aq) + NO2–(aq) K=7.2 X 10-4 When 1.00 mole of HNO2 is added to 1.00 L of water, the H+ concentration at equilibrium is 0.0265 M.A) Calculate the value of Q if 1.00 L of water is added? B) How will reaction shift if 1.00 L of water is added?arrow_forwardSuppose a certain copolymer elastomeric material “styrene-butadiene rubber”) contains styrene ("S") monomers –(C8H8)– and butadiene ("B") monomers –(C4H6)– and that their numerical ratio S:B = 1:8. What is the mass ratio mS:mB of the two monomers in the material? What is the molecular mass M of a macromolecule of this copolymer with degree of polymerization n = 60,000? Data: AC = 12.01 u, AH = 1.008 u.arrow_forward
- Lab Questions from Lab: Gravimetric Determination of Calcium as CaC2O4•H2O What is the purpose of the methyl red indicator? Why does a color change to yellow tell you that the reaction is complete? Why is the precipitate rinsed with ice-cold water in step 4? Why not room temperature or hot water? Why is it important that the funnels be placed in a desiccator before weighing (steps 1 and 5)?arrow_forwardWhat mass of ethylene glycol, HOCH2CH2OH, Mustbe added to 5.50 kg of water to antifreeze that would work for the car radiator to -10.0 degrees celcius? MM (g/mol): 62.07arrow_forwardWhat is the molarity of a 0.393 m glucose solution if its density is 1.16 g/mL? MM glucose 180.2 g/molarrow_forward
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