Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 2.2, Problem 41PPS

a.

To determine

To state: the equation of the model .

a.

Expert Solution
Check Mark

Answer to Problem 41PPS

The equation is 1.75x+1.50y=525 .

Explanation of Solution

Given information:

Latonya earns commission of $1.75 for each magazine subscription she sells and for each newspaper she gets $1.50 .

Formula used:

A linear function is a function with ordered pairs that satisfy a linear equation . The equation can be written in the form f(x)=mx+b where m , b are real numbers.

Calculation:

According to the model ,

Money earned by selling each magazine is $1.75

Money earned by selling each newspaper is $1.50

Let the number of magazines be x ,

Let the number of newspaper be y .

The goal is $525

We, have

  1.75x+1.50y=525

Hence, the equation is 1.75x+1.50y=525 .

b.

To determine

To graph: The equation 1.75x+1.50y=525

b.

Expert Solution
Check Mark

Explanation of Solution

Given information:

The equation 1.75x+1.50y=525 .

Graph:

  Algebra 2, Chapter 2.2, Problem 41PPS

Figure 1.

Interpretation:

The linear equation 1.75x+1.50y=525 is represented above. The x -axes represents the number of magazines sold whereas the y -axes represent the number of newspaper sold.

The x -intercept is at 300 and y -intercept is at 350.

c.

To determine

To calculate: the total goal.

c.

Expert Solution
Check Mark

Answer to Problem 41PPS

The total money earned is $475 that does not meet the goal of $525 .

Explanation of Solution

Given information:

  1.75x+1.50y=525

Formula used:

Dependent variable and Independent variable: x is independent variable whereas y is dependent variable because the value of y depends on value of x .

Calculation:

Consider ,

  1.75x+1.50y=525

The number of magazine sold is 100.

The number newspaper sold is 200.

Substituting these values in equation we get,

  =1.75(100)+1.50(200)=525=175+300=525=475525.

Thus, the target is not completed.

Chapter 2 Solutions

Algebra 2

Ch. 2.1 - Prob. 5CYUCh. 2.1 - Prob. 6CYUCh. 2.1 - Prob. 7CYUCh. 2.1 - Prob. 8CYUCh. 2.1 - Prob. 9CYUCh. 2.1 - Prob. 10CYUCh. 2.1 - Prob. 11PPSCh. 2.1 - Prob. 12PPSCh. 2.1 - Prob. 13PPSCh. 2.1 - Prob. 14PPSCh. 2.1 - Prob. 15PPSCh. 2.1 - Prob. 16PPSCh. 2.1 - Prob. 17PPSCh. 2.1 - Prob. 18PPSCh. 2.1 - Prob. 19PPSCh. 2.1 - Prob. 20PPSCh. 2.1 - Prob. 21PPSCh. 2.1 - Prob. 22PPSCh. 2.1 - Prob. 23PPSCh. 2.1 - Prob. 24PPSCh. 2.1 - Prob. 25PPSCh. 2.1 - Prob. 26PPSCh. 2.1 - Prob. 27PPSCh. 2.1 - Prob. 28PPSCh. 2.1 - Prob. 29PPSCh. 2.1 - Prob. 30PPSCh. 2.1 - Prob. 31PPSCh. 2.1 - Prob. 32PPSCh. 2.1 - Prob. 33PPSCh. 2.1 - Prob. 34PPSCh. 2.1 - Prob. 35HPCh. 2.1 - Prob. 36HPCh. 2.1 - Prob. 37HPCh. 2.1 - Prob. 38HPCh. 2.1 - Prob. 39HPCh. 2.1 - Prob. 40HPCh. 2.1 - Prob. 41HPCh. 2.1 - Prob. 42HPCh. 2.1 - Prob. 43HPCh. 2.1 - Prob. 44HPCh. 2.1 - Prob. 45STPCh. 2.1 - Prob. 46STPCh. 2.1 - Prob. 47STPCh. 2.1 - Prob. 48STPCh. 2.1 - Prob. 49STPCh. 2.1 - Prob. 50STPCh. 2.1 - Prob. 51STPCh. 2.1 - Prob. 52STPCh. 2.1 - 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Prob. 2ACYPCh. 2.7 - Prob. 2BCYPCh. 2.7 - Prob. 3ACYPCh. 2.7 - Prob. 3BCYPCh. 2.7 - Prob. 4ACYPCh. 2.7 - Prob. 4BCYPCh. 2.7 - Prob. 5CYPCh. 2.7 - Prob. 1CYUCh. 2.7 - Prob. 2CYUCh. 2.7 - Prob. 3CYUCh. 2.7 - Prob. 4CYUCh. 2.7 - Prob. 5CYUCh. 2.7 - Prob. 6CYUCh. 2.7 - Prob. 7CYUCh. 2.7 - Prob. 8CYUCh. 2.7 - Prob. 9CYUCh. 2.7 - Prob. 10PPSCh. 2.7 - Prob. 11PPSCh. 2.7 - Prob. 12PPSCh. 2.7 - Prob. 13PPSCh. 2.7 - Prob. 14PPSCh. 2.7 - Prob. 15PPSCh. 2.7 - Prob. 16PPSCh. 2.7 - Prob. 17PPSCh. 2.7 - Prob. 18PPSCh. 2.7 - Prob. 19PPSCh. 2.7 - Prob. 20PPSCh. 2.7 - Prob. 21PPSCh. 2.7 - Prob. 22PPSCh. 2.7 - Prob. 23PPSCh. 2.7 - Prob. 24PPSCh. 2.7 - Prob. 25PPSCh. 2.7 - Prob. 26PPSCh. 2.7 - Prob. 27PPSCh. 2.7 - Prob. 28PPSCh. 2.7 - Prob. 29PPSCh. 2.7 - Prob. 30PPSCh. 2.7 - Prob. 31PPSCh. 2.7 - Prob. 32PPSCh. 2.7 - Prob. 33PPSCh. 2.7 - Prob. 34PPSCh. 2.7 - Prob. 35PPSCh. 2.7 - Prob. 36PPSCh. 2.7 - Prob. 37PPSCh. 2.7 - Prob. 38PPSCh. 2.7 - Prob. 39PPSCh. 2.7 - Prob. 40PPSCh. 2.7 - Prob. 41PPSCh. 2.7 - Prob. 42PPSCh. 2.7 - 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