Concept explainers
To analyze:
The presence of cheek and chin dimples is dominant to the lack of dimples, and the ability to taste the compound PTC is dominant to the failure to taste the compound, in humans. Both these qualities are autosomal and unlinked. The allele frequencies for dimples are
Calculate the frequency of genotypes for each gene and the frequency of each
Estimate the expected frequencies of the four probable phenotype combination: Dimpled nontasters, dimpled tasters, undimpled tasters, and undimpled nontasters.
Introduction:
Hardy-Weinberg explains that allelic frequency in a population can be maintained but population should fulfill some criteria i.e. there should be random mating, no mutation, large
Hardy-Weinberg mathematical equation to calculate the allelic and genotypic frequency is
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GENETIC ANALYSIS: AN INTEG. APP. W/MAS
- Give the most likely genotypes of the parent in each cross (use B for the burnsi allele and B+ for pipiens allele).arrow_forwardIn Ayrshire cattle, the spotting of the animals can be either red and white or mahogany and white. The mahogany and white phenotype is caused by the allele SM. The red and white phenotype is controlled by the allele SR. The table below shows the relationship between genotype and phenotype for males and females:arrow_forwardA pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?arrow_forward
- Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?arrow_forwardExplainarrow_forwardUsing the example of pea color in Mendel’s pea plants, can you devise equations to determine the allele frequencies of A and a from the genotype frequencies of aa, Aa, and AA?arrow_forward
- Given the allelic frequency of A = .5 , answer the following 1. What is the homozygous dominant frequency ? 2. What is the allellc of a? 3. What is the heterozygous frequency ?arrow_forwardUsing the two equations, p + q = 1 and p2 + 2pq + q2 = 1, answer the following questions. Maple Syrup Urine Disease (MSUD) is an autosomal recessive condition that causes intellectual and physical disabilities, difficulty feeding, and a sweet maple syrup odor to the urine. In Costa Rica, the incidence of MSUD is calculated as approximately 1 in 8,000 newborns. Calculate the allele frequencies for the normal and disease alleles.arrow_forwardSuppose that a geneticist studies a series of characteristics in monozygotic twins and dizygotic twins. He finds various rates of phenotypic concordance for the characteristics, as shown in the table. Rate of phenotypic concordance (%) Characteristic Monozygotic Dizygotic migraine headache 60 30 eye color 100 40 measles 90 90 clubfoot 30 10 high blood pressure 70 40 handedness 70 70 tuberculosis Classify each characteristic according to whether the corresponding rates of concordance indicate a genetic influence, an environmental influence, or both genetic and environmental influences.arrow_forward
- If the environmental variance increase and the genetic variance components remain the same what will the effect be on heritability? Select one: O a. Broad-sense heritability will increase O b. There will be no change. O c. Broad-sense heritability will increase, but narrow sense heritability will decrease. O d. Narrow-sense heritability will increase O e. Broad-sense heritability will decrease /quiz/attempt.php?attempt=1173673&cmid=3837312&page=4# 3 с $ 4 G Search or type URL % 5 MacBook Pro 6 & 8 9 1arrow_forwardUsing the two Hardy-Weinberg equations, calculate the allelic and genotypic frequencies. Tongue rollers [R_-]= 840, Non rollers [rr] = 160, Total = 1000 1. What are the phenotypic frequencies for tongue rollers? 0.84 2. What are the phenotypic frequencies for non-tongue rollers? 0.16 3. What is the allelic frequency for r? 0.4 4. What is the allelic frequency for R? 0.6 5. What is the homozygous dominant frequency? 6. What is the heterozygous frequency? 7. What is the homozygous recessive frequency?arrow_forwardMatch the exception to Mendel's rules to its example. if there are three genes that determine freckledness v and the more dominant alleles a person has the more freckles they exhibit if there were FR and FD and f alleles for freckles where FR codes for red freckles and FB codes for brown freckles and when FR and FB are both present the individual has as many red freckles as an FRER individual and as many brown freckles as an FBFB individual A. incomplete dominance B. polygenic trait C. sex-linkage if a homozygous dominant individual has freckles, a homozygous individual has no freckles and a heterozygote has half as many freckles as a homozygous dominant D. pleiotropy E. epistasis if the freckle gene also codes for curly eyelashes and F. environmental effects on gene expression arched eyebrows G. codominance if a person has their freckles removed by a medical procedure H. trait follows Mendel's Rules v if only males can exhibit freckles if FF and Ff have the same amount of freckles and…arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning