DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 22, Problem 26RQ
The typical value of a coefficient of variation in metal-cutting tool life distributions is 0.3. How could it be reduced?
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A process engineer is trying to improve the life of a cutting tool. He has run a 23 experiment using (1) cutting speed, (2) metal hardness, (3) and cutting angle as the factors. The data from the 2 replicates are shown below.
(a) Do any of the 3 factors affect tool life?
(b)what combination of the factor levels produces the longest tool life?
(c) Is there a combination of cutting speed and cutting angle that always gives good results regardless of metal hardness?
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A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy= 1200 ksi. If the width of cut is 0.30 in. and the student set a rake angle of 0° and a cutting speed of 200 ft/ min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
Chapter 22 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 22 - For metal-cutting tools, what is the most...Ch. 22 - What is hot hardness compared to hardness?Ch. 22 - Prob. 3RQCh. 22 - Why is impact strength an important property in...Ch. 22 - Cemented carbide tools are made by a powder...Ch. 22 - What are the primary considerations in tool...Ch. 22 - What is the general strategy behind coated tools?Ch. 22 - Prob. 8RQCh. 22 - How is a CBN tool manufactured?Ch. 22 - Prob. 10RQ
Ch. 22 - Prob. 11RQCh. 22 - Discuss the constraints in the selection of a...Ch. 22 - What does cemented mean in the manufacture of...Ch. 22 - What advantage do ground carbide inserts have over...Ch. 22 - What is a chip groove?Ch. 22 - What is the DCL?Ch. 22 - Suppose you made four beams out of carbide, HSS,...Ch. 22 - Multiple coats or layers are put on the carbide...Ch. 22 - What tool material would you recommend for...Ch. 22 - What makes the process that makes TiC coatings for...Ch. 22 - Why does a TiN-coated tool consume less power than...Ch. 22 - For what work material are CBN tools more commonly...Ch. 22 - Why is CBN better for machining steel than...Ch. 22 - What is the typical coefficient of variation for...Ch. 22 - What is meant by the statement Tool life is a...Ch. 22 - The typical value of a coefficient of variation in...Ch. 22 - Machinability is defined in many ways. Explain how...Ch. 22 - What are the chief functions of cutting fluids?Ch. 22 - Prob. 29RQCh. 22 - Why is the PVD process used to coat HSS tools?Ch. 22 - Why is there no universal cutting tool material?Ch. 22 - What is an 18-4-1 HSS composed of?Ch. 22 - Over the years, tool materials have been developed...Ch. 22 - Why is the rigidity of the machine tool an...Ch. 22 - Explain how it can be that the tool wears when it...Ch. 22 - What is a honed edge on a cutting tool and why is...Ch. 22 - Suppose you have a turning operation using a tool...Ch. 22 - A 2 in.-diameter bar of steel was turned at 284...Ch. 22 - Prob. 3PCh. 22 - The following data have been obtained for...Ch. 22 - In the insert is set with a 0 side cutting-edge...Ch. 22 - Prob. 6PCh. 22 - Here is a single point tool. Identify angles A...Ch. 22 - Figure 22.B gives data for cutting speed and tool...
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- 2. The following data was obtained from an orthogonal cutting test: Rake angle = 20° Cutting speed = 100 m/min Chip length before cutting = 29.4 mm Chip length after cutting = 12.9 mm Vertical cutting force 1050 N Horizontal cutting force = 630 N Using Merchant's analysis, calculate (a) resultant force (c) friction force and friction angle (b) shear plane angle (d) total work donearrow_forward(b) A 400 mm long, 19.5 mm diameter of 304 stainless steel rod (assume specific energy of steel is 4 W.s/mm³) is being reduced in diameter to 17 mm by turning on a lathe machine. The spindle rotates at N = 700 rpm, and the tool is traveling at an axial speed of 300 mm/min. Calculate: (i) (ii) (iii) (iv) (v) cutting speed material removal rate cutting time power dissipated cutting forcearrow_forward%9. lu. O V;YA Q1 What is the difference between direct shear and indirect cutting? Q2_What are the factors affecting fatigue Q3_What is the difference between hardness and micro-hardness Q4_What is the fatigue limit? Q5_What is strain hardness? Q6 What is the difference between true stress and engineering stress Q7_What is the difference between true strain and engineering strain? What is the relationship that binds them? Q8_ When do the "ears" appear in drawn cup, through cup drawing tests? Q9 Could we use results of tensile tests predict impact failure behavior, why? Q10_Could you estimate ductile-to-brittle transition temperatures for metals having hexagonal close-packed structure, why? Q11 Can creep of metals happen in room temperature, when? Solve a question 1_2_3_4_5_6_7_8_9_10_11 IIarrow_forward
- Note: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forwardManufacturingarrow_forwardIn an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work donearrow_forward
- Clean solutionarrow_forward2 1.42 The tool-life curve for ceramic tools in Fig. 21.17 is to the right of those for other tool materials. Why?arrow_forwardDraw the forces and angles involved in the cutting process and calculate shear angle (Ø), friction coefficient and tangential force ,cutting force = 80 kN, resultant of forces =100KN. friction force=75KN, rake angle =20' undeformed chip thickness = 0.65mm and deformed chip thickness = 0.72mm vjallarrow_forward
- Q2 Describe FOUR (4) major independent and dependent variables that influence cutting process. (a)arrow_forward3. Draw the forces and angles involved in the cutting process and calculate shear angle (Ø), friction coefficient and tangential force if ,cutting force = 80 kN , resultant of forces =100kN , friction force=75KN, rake angle =20° undeformed chip thickness = 0.65mm and deformed chip thickness 0.72mm. %3Darrow_forward2 1.4 1 The Taylor tool-life equation is directly applicable to flank wear. Explain whether or not it can be used to model tool life if other forms of wear are dominant.arrow_forward
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