DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 22, Problem 3P
(a)
To determine
The tool material used between Silicon nitride and PCBN tool.
(b)
To determine
The reason to recommend the above material.
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A HSS tool is used to turn a steel workpart that is 300 mm long and 80 mm in diameter. The parameters in the Taylor equation are: n = 0.13 and C = 75 (m/min) for a feed of 0.4 mm/rev. The operator and machine tool rate = $30.00/hr, and the tooling cost per cutting edge = $4.00. It takes 2.0 min to load and unload the workpart and 3.50 min to change tools. Determine:
Tutting speed for maximum production rate,
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determine cutting speed for minimum cost.
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Chapter 22 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 22 - For metal-cutting tools, what is the most...Ch. 22 - What is hot hardness compared to hardness?Ch. 22 - Prob. 3RQCh. 22 - Why is impact strength an important property in...Ch. 22 - Cemented carbide tools are made by a powder...Ch. 22 - What are the primary considerations in tool...Ch. 22 - What is the general strategy behind coated tools?Ch. 22 - Prob. 8RQCh. 22 - How is a CBN tool manufactured?Ch. 22 - Prob. 10RQ
Ch. 22 - Prob. 11RQCh. 22 - Discuss the constraints in the selection of a...Ch. 22 - What does cemented mean in the manufacture of...Ch. 22 - What advantage do ground carbide inserts have over...Ch. 22 - What is a chip groove?Ch. 22 - What is the DCL?Ch. 22 - Suppose you made four beams out of carbide, HSS,...Ch. 22 - Multiple coats or layers are put on the carbide...Ch. 22 - What tool material would you recommend for...Ch. 22 - What makes the process that makes TiC coatings for...Ch. 22 - Why does a TiN-coated tool consume less power than...Ch. 22 - For what work material are CBN tools more commonly...Ch. 22 - Why is CBN better for machining steel than...Ch. 22 - What is the typical coefficient of variation for...Ch. 22 - What is meant by the statement Tool life is a...Ch. 22 - The typical value of a coefficient of variation in...Ch. 22 - Machinability is defined in many ways. Explain how...Ch. 22 - What are the chief functions of cutting fluids?Ch. 22 - Prob. 29RQCh. 22 - Why is the PVD process used to coat HSS tools?Ch. 22 - Why is there no universal cutting tool material?Ch. 22 - What is an 18-4-1 HSS composed of?Ch. 22 - Over the years, tool materials have been developed...Ch. 22 - Why is the rigidity of the machine tool an...Ch. 22 - Explain how it can be that the tool wears when it...Ch. 22 - What is a honed edge on a cutting tool and why is...Ch. 22 - Suppose you have a turning operation using a tool...Ch. 22 - A 2 in.-diameter bar of steel was turned at 284...Ch. 22 - Prob. 3PCh. 22 - The following data have been obtained for...Ch. 22 - In the insert is set with a 0 side cutting-edge...Ch. 22 - Prob. 6PCh. 22 - Here is a single point tool. Identify angles A...Ch. 22 - Figure 22.B gives data for cutting speed and tool...
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- In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fvarrow_forwardFind the machining time, in seconds, and the rate of material removing in mmA3;sec for a turning operation having the following information: 1- Wp diameter is 80mm, 2- the length is 0.12m, 3- the cutting speed is 80m/min, 4- feed i50.5 mm/rev and 5- the depth of cut is 0.002m.arrow_forwardA turning operation is performed with HSS tooling on mild steel, with Taylor tool life parameters n = 0.12, C = 60 m/min. Work part length = 450 mm and diameter = 80 mm. Feed = 0.20 mm/rev. Handling time per piece = 4.0 min, and tool change time = 1.5 min. Cost of machine and operator = $27/hr, and tooling cost = $2 per cutting edge. Find the a. cutting speed for maximum production rate and b. cutting speed for minimum cost Equations used n *-=c(")* Vmax = C 1-n Tt Vmin = C =c(₁" n 1 n Co n CoTt + Ct narrow_forward
- Expert Q&A Done The top surface of a rectangular workpart is machined using a peripheral milling operation. The workpart is 735 mm long by 50 mm wide by 95 mm thick. The milling cutter, which is 60 mm in diameter and has five teeth, overhangs the width of the part equally on both sides. Cutting speed = 80 m/min, chip load = 0.30 mm/tooth, and depth of cut = 7.5 mm. (a) Determine the time required to make one pass across the surface, given that the setup and machine settings provide an approach distance of 5 mm before actual cutting begins and an overtravel distance of 25 mm after 1.2 9. 20 65 73 actual cutting has finished v in seconds. (b) What is the maximum material 3.9 239 removal rate during the cut v in mm3/sec? 0.127 5arrow_forwardA 600mm*30mm flat surface of a plate is to be finish machined on a shaper .The plate has been fixed with 600 mm side along the tool travel direction. If the tool over-travel at each end of the plate is 20 mm, average cutting speed is 8 m/min, feed rate is 0.3 mm/stroke and the ratio of return time to cutting time of the tool is 1:2 Determine time required for machining?arrow_forwardQ1. Calculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation. Answer Q2. A gray cast iron surface 280 wide and 540mm long may be machined either on a vertical milling machine, using a 100mm - diameter face mill having eight inserted HSS teeth, or on a horizontal milling machine using an HSS slab mill with eight teeth on a 200-mm. diameter. Which machine has the faster cutting time? The values of feed per tooth and cutting speed for both processes are 0.4mm/tooth and 80m/min, respectively. The depth of cut = 3.0 mm and assume A and O equal to 5. Answerarrow_forward
- Whats the answer for this please ?arrow_forwardThree tool materials are to be compared for the same finish turning operation on a batch of 100 steel parts: high speed steel, cemented carbide, and ceramic. For the high speed steel tool, the 170 Taylor equation parameters are: n = 0.125 and C = 70. The price of the HSS tool is $15.00 and it is estimated that it can be ground and reground 15 times at a cost of $1.50. Tool change time = 3 min. Both carbide and ceramic tools are in insert form and can be held in the same mechanical toolholder. The Taylor equation parameters for the cemented carbide are: n = 0.25 and C = 500; and for the ceramic: n = 0.6 and C = 3,000. The cost per insert for the carbide = $6.00 and for the ceramic = $8.00. Number of cutting edges per insert in both cases = 6. Tool change time = 1.0 min for both tools. Time to change parts = 2.0 min. Feed = 0.25 mm/rev, and depth = 3.0 mm. The cost of machine time = $30/hr. The part dimensions are: diameter = 56.0 mm and length = 290 mm. Setup time for the batch is 2.0…arrow_forwardI need a solution within 15 minutesarrow_forward
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