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Identify the structures of D and E, isomers of molecular formula
a. IR absorption for D at
b. IR absorption for E at
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- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardDraw the structure of molecular formula C8H10O that produced the 1H NMR spectra shown below. The IR spectrum does not show a broad absorbance at 3300 cm–1 or a strong absorbance at 1710 cm–1.arrow_forwardDetermine the structure of an alcohol with molecular formula C5H12O that exhibits the following signals in its 13C NMR spectra: a. Broadband decoupled: 73.8 δ, 29.1δ, and 9.5 δ b. DEPT-90: 73.8 δ c. DEPT-135: positive signals at 73.8 δ, and 9.5 δ, and negative signal at 29.1δ,arrow_forward
- Identify the structures of D and E, isomers of molecular formulaC6H12O2, from their IR and 1H NMR data. Signals at 1.35 and 1.60 ppm inthe 1H NMR spectrum of D and 1.90 ppm in the 1H NMR spectrum of Eare multiplets.arrow_forwardAn unknown compound has the formula C3H6O2. Elucidate its structure by scrutinizing its 1H NMR spectra, shown. Specifically, label each different type of H atom in the final structure with its NMR chemical shift in ppm.arrow_forwardThymol (molecular formula C10H14O) is the major component of the oil of thyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and 1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose a possible structure for thymol.arrow_forward
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- A compound with molecular formula C8H8O3 exhibits the following IR, 1H NMR and 13C NMR spectra. Deduce the structure of this compound.arrow_forwardCompound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forwardThe proton nmr is 2H doublet at about 3.4 1H nonet at 1.5 6H doublet at about 1.parrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning