Chapter 22, Problem 22.19P

(a)

Interpretation Introduction

Interpretation:

Number of particles in $\text{1}\text{g}$ silica has to be calculated.

Concept Introduction:

Formula to calculate volume of a sphere is calculated as follows:

    $\text{Volume}=\frac{4}{3}\text{π}{\left(\text{radius}\right)}^3$

Formula to calculate mass is as follows:

    $\text{Mass}=\left(\text{Volume}\right)\left(\text{Density}\right)$

(b)

Interpretation Introduction

Interpretation:

Surface area of $\text{1}\text{g}$ solid silica particle has to be calculated.

Concept Introduction:

Formula to calculate volume of a sphere is calculated as follows:

    $\text{Volume}=\frac{4}{3}\text{π}{\left(\text{radius}\right)}^3$

Formula to calculate mass is as follows:

    $\text{Mass}=\left(\text{Volume}\right)\left(\text{Density}\right)$

Formula to calculate surface area of a sphere is as follows:

    $\text{Surface}\text{area}=\text{4π}{\left(\text{radius}\right)}^2$

(c)

Interpretation Introduction

Interpretation:

Porosity of the particle has to be discussed.

Concept Introduction:

The difference of observed and calculated surface area of a solid determines the porosity and irregular structure of the particles.