(a)
Interpretation:
To write the balanced equation for the reaction of
Concept introduction:
Reducing agent are the species that reduces another species and itself gets oxidized in a
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(b)
Interpretation:
The mass of silver produced in the reaction has to be stated.
Concept introduction:
Reducing agent are the species that reduces another species and itself gets oxidized in a chemical reaction. A common example of reducing agent is sodium borohydride. The formula for sodium borohydride is
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
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Chapter 21 Solutions
Chemistry & Chemical Reactivity
- Phosphate buffers are important in regulating the pH of intracellular fluids. If the concentration ratio of H2PO4/HPO42 in a sample of intracellular fluid is 1.1: 1, what is the pH of this sample of intracellular fluid? H2PO4(aq)HPO42(aq)+H+(aq)Ka=6.2108arrow_forwardIn the commercial preparation of aluminum, aluminum oxide, Al2O3, is electrolyzed at 1000C. (The mineral cryolite is added as a solvent.) Assume that the cathode reaction is Al3+3eAl How many coulombs of electricity are required to give 3.9 kg of aluminum?arrow_forwardWrite balanced net ionic equations for the following reactions in acid solution. (a) Liquid hydrazine reacts with an aqueous solution of sodium bromate. Nitrogen gas and bromide ions are formed. (b) Solid phosphorus (P4) reacts with an aqueous solution of nitrate to form nitrogen oxide gas and dihydrogen phosphate (H2PO4-) ions. (c) Aqueous solutions of potassium sulfite and potassium permanganate react. Sulfate and manganese(II) ions are formed.arrow_forward
- The amount of sodium hypochlorite in a bleach solution can be determined by using a given volume of bleach to oxidize excess iodide ion to iodine; ClO- is reduced to Cl-. The amount of iodine produced by the redox reaction is determined by titration with sodium thiosulfate, Na2S2O3; I2 is reduced to I-. The sodium thiosulfate is oxidized to sodium tetrathionate, Na2S4O6. In this analysis, potassium iodide was added in excess to 5.00 mL of bleach (d=1.00g/cm3) . If 25.00 mL of 0.0700 M Na2S2O3 was required to reduce all the iodine produced by the bleach back to iodide, what is the mass percent of NaClO in the bleach?arrow_forwardAluminum is produced commercially by the electrolysis of Al2O3 in the presence of a molten salt. If a plant has a continuous capacity of 1.00 million A, what mass of aluminum can be produced in 2.00 h?arrow_forwardA mixture of xenon and ?uorine was heated. A sample of the white solid that formed reacted with hydrogen to yield 81 ml of xenon (at STP) and hydrogen ?uoride, which was collected in waiter, giving a solution of hydro?uoric acid. The hydro?uoric acid solution was titrated, and 68.43 mL of 0.3172 M sodium hydroxide was required to reach the equivalence point. Determine the empirical formula for the white solid and write balanced Chemical equations for the reactions involving xenon.arrow_forward
- Which of the following elements is most likely to be used to prepare La by the reduction of La2O3: Al, C, or Fe? Why?arrow_forwardThe amount of sodium hypochlorite in a bleach solution can be determined by using a given volume of bleach to oxidize excess iodide ion to iodine, because the reaction goes to completion. The amount of iodine produced is then determined by titration with sodium thiosulfate, Na2S2O3, which is oxidized to sodium tetrathionate, Na2S4O6. Potassium iodide was added in excess to 5.00 mL of bleach (density = 1.00 g/mL). This solution, containing the iodine released in the reaction, was titrated with 0.100 M Na2S2O3. If 34.6 mL of sodium thiosulfate was required to reach the endpoint (detected by disappearance of the blue color of the starch iodine complex), what was the mass percentage of NaClO in the bleach?arrow_forwardIn an analytical determination of arsenic, a solution containing arsenious acid, H3AsO3, potassium iodide, and a small amount of starch is electrolyzed. The electrolysis produces free iodine from iodide ion, and the iodine immediately oxidizes the arsenious acid to hydrogen arsenate ion, HAsO42. I2(aq)+H3AsO3(aq)+H2O(l)2I(aq)+HAsO42(aq)+4H+(aq) When the oxidation of arsenic is complete, the free iodine combines with the starch to give a deep blue color. If, during a particular run, it takes 65.4 s for a current of 10.5 mA to give an endpoint (indicated by the blue color), how many grams of arsenic are present in the solution?arrow_forward
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