General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN: 9781305580343
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher: Cengage Learning
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Chapter 21, Problem 21.203QP
Interpretation Introduction

Interpretation:

  • Chemical equation for given reaction has to be written.
  • At 2000°C the equilibrium constant for this reaction has to be calculated by using thermodynamic data and respective approximation.

Expert Solution & Answer
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Answer to Problem 21.203QP

  • Chemical equation for given reaction is

CO2(g) + C(graphite)2CO(g)

  • Equilibrium constant for this reaction at 2000°C is 1.6×105

Explanation of Solution

To write: Chemical equation for given reaction

Carbon burns in a air it gives Carbon dioxide and carbon monoxide also presented because the product the hot Carbon is react with Carbon dioxide.

Thermodynamic data and the reaction gives the equation as follows,

CO2(g) + C(graphite)2CO(g)

To determine: constant for this reaction at 2000°C

        CO2(g) + C(graphite)2CO(g)  ΔHf0    -393.5     0-110kJ/mol  S°213.75.740197.5J/mol.K

Standard enthalpy change and standard entropy change is calculated.

        ΔHrxn°= [2(-110.5) - (-393.5)] kJ = 172.5 kJ        ΔSrxn°= [2(197.5) - (213.7) - (5.740)] J/K = 175.56 J/K = 0.17556 kJ/K

Assume that change in enthalpy and entropy they do not vary with temperature and use them to determine ΔG at greater temperature.

        ΔGrxn=ΔHrxn-TΔSrxn(172.5 kJ) - (2273 K)(0.17556 kJ/K) = -226.54 kJ 

Write the free-energy change in terms of equilibrium constant

        ΔGrxn= -RTlnK= -226.54 kJ/molRearrange and solve for K.        lnK= -ΔGRT-(-226.54kJ/mol)(8.314×10-3kJ/mol•K)(2273K)= 11.988        K=e11.988= 1.60×105= 1.6×105

Conclusion

  • Chemical equation for given reaction was given as,

CO2(g) + C(graphite)2CO(g)

  • Equilibrium constant for this reaction at 2000°C was calculated as 1.6×105

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Chapter 21 Solutions

General Chemistry - Standalone book (MindTap Course List)

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