Chapter 21, Problem 21.126QP

(a)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The given equation complete and balanced.

Answer to Problem 21.126QP

The complete and balanced equation of the given equation is:

${\text{NaHCO}}_3{\text{(aq) + HC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}\stackrel{}{\to }{\text{ CO}}_2{\text{(g) + H}}_{\text{2}}{\text{O(l) + NaC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}$

Explanation of Solution

Given Equation:

${\text{NaHCO}}_3{\text{(aq) + HC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}\stackrel{}{\to }$

Complete Equation:

A complete equation will have same present on both sides of the equation.

The above equation can be completed by writing as follows,

${\text{NaHCO}}_3{\text{(aq) + HC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}\stackrel{}{\to }{\text{ CO}}_2{\text{(g) + H}}_{\text{2}}{\text{O(l) + NaC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}$

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side	Atom	Product side
3	$\text{C}$	3
5	$\text{O}$	5
5	$\text{H}$	5
1	$\text{Na}$	1

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

${\text{NaHCO}}_3{\text{(aq) + HC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}\stackrel{}{\to }{\text{ CO}}_2{\text{(g) + H}}_{\text{2}}{\text{O(l) + NaC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}$

Conclusion

The complete and balanced equation of the given equation is written as:

${\text{NaHCO}}_3{\text{(aq) + HC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}\stackrel{}{\to }{\text{ CO}}_2{\text{(g) + H}}_{\text{2}}{\text{O(l) + NaC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{(aq)}$

(b)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The given equation complete and balanced.

Answer to Problem 21.126QP

The complete and balanced equation of the given equation is:

${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }2{\text{CaCO}}_{\text{3}}(s){\text{ + 2H}}_{\text{2}}\text{O(l)}$

Explanation of Solution

Given Equation:

${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }$

Complete equation:

A complete equation will have same present on both sides of the equation.

The above equation can be completed by writing as follows,

${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }{\text{ CaCO}}_{\text{3}}(s){\text{ + H}}_{\text{2}}\text{O(l)}$

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }{\text{ CaCO}}_{\text{3}}(s){\text{ + H}}_{\text{2}}\text{O(l)}$

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side	Atom	Product side
2	$\text{C}$	1
8	$\text{O}$	4
3	$\text{H}$	2
2	$\text{Ca}$	1

Multiply both the products on the product side by two and balance the equation again.

${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }2{\text{CaCO}}_{\text{3}}(s){\text{ + 2H}}_{\text{2}}\text{O(l)}$

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side	Atom	Product side
2	$\text{C}$	2
8	$\text{O}$	8
4	$\text{H}$	4
2	$\text{Ca}$	2

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  ${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }2{\text{CaCO}}_{\text{3}}(s){\text{ + 2H}}_{\text{2}}\text{O(l)}$

Conclusion

The complete and balanced equation of the given equation is written as:

${\text{Ca(HCO}}_3{\text{)}}_{\text{2}}{\text{(aq) + Ca(OH)}}_{\text{2}}\text{(aq)}\stackrel{}{\to }2{\text{CaCO}}_{\text{3}}(s){\text{ + 2H}}_{\text{2}}\text{O(l)}$