General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN: 9781305580343
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher: Cengage Learning
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Chapter 21, Problem 21.116QP

(a)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balancing the equation:

  • There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.
  • Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized.  Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
  • Oxidation reduction and reduction reaction occur simultaneously in same reaction.

To Write: The given equation complete and balanced.

(a)

Expert Solution
Check Mark

Answer to Problem 21.116QP

The complete and balanced equation for the given equation is:

3Pb(NO3)2(aq) + 2Al(s) 3Pb(s) + 2Al(NO3)3(aq)

Explanation of Solution

Given Equation:

Pb(NO3)2(aq) + Al(s)

Complete Equation:

A complete equation will have same elements present on both sides of the equation.

The above equation can be completed by writing as follows,

Pb(NO3)2(aq) + Al(s) Pb(s) + Al(NO3)3(aq)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Pb(NO3)2(aq) + Al(s) Pb(s) + Al(NO3)3(aq)

Reactant side Atom Product side
1 Al 1
2 (NO3) 3
1 Pb 1

To balance the above equation, multiply Pb(NO3)2 and Pb by three and Al(s) and Al(NO3)3 by two

3Pb(NO3)2(aq) + 2Al(s) 3Pb(s) + 2Al(NO3)3(aq)

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
2 Al 2
6 (NO3) 6
3 Pb 3

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  3Pb(NO3)2(aq) + 2Al(s) 3Pb(s) + 2Al(NO3)3(aq)

Conclusion

The complete and balanced equation of the given equation is written as:

3Pb(NO3)2(aq) + 2Al(s) 3Pb(s) + 2Al(NO3)3(aq)

(b)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balancing the equation:

  • There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.
  • Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized.  Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
  • Oxidation reduction and reduction reaction occur simultaneously in same reaction.

To Write: The given equation complete and balanced.

(b)

Expert Solution
Check Mark

Answer to Problem 21.116QP

The complete and balanced equation of the given equation is:

Pb(NO3)2 + Na2CrO4(aq) PbCrO4(s) + 2NaNO3(aq)

Explanation of Solution

Given Equation:

Pb(NO3)2 + Na2CrO4(aq)

Complete equation:

A complete equation will have same present on both sides of the equation.

The above equation can be completed by writing as follows,

Pb(NO3)2 + Na2CrO4(aq) PbCrO4(s) + NaNO3(aq)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

Pb(NO3)2 + Na2CrO4(aq) PbCrO4(s) + NaNO3(aq)

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
1 Pb 1
10 O 7
2 Na 1
2 N 1
1 Cr 1

To balance the above equation, multiply NaNO3 on the product side by two.

Pb(NO3)2 + Na2CrO4(aq) PbCrO4(s) + 2NaNO3(aq)

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
1 Pb 1
10 O 10
2 Na 2
2 N 2
1 Cr 1

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  Pb(NO3)2 + Na2CrO4(aq) PbCrO4(s) + 2NaNO3(aq)

Conclusion

The complete and balanced equation of the given equation is written as:

Pb(NO3)2 + Na2CrO4(aq) PbCrO4(s) + 2NaNO3(aq)

(c)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balancing the equation:

  • There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.
  • Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized.  Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
  • Oxidation reduction and reduction reaction occur simultaneously in same reaction.

To Write: The given equation complete and balanced.

(c)

Expert Solution
Check Mark

Answer to Problem 21.116QP

The complete and balanced equation for the given equation is:

Al2(SO4)3(aq) + 6LiOH(aq) 2Al(OH)3(s) + 3Li2SO4(aq)

Explanation of Solution

Given Equation:

Al2(SO4)3(aq) + dilute LiOH(aq)

Complete Equation:

A complete equation will have same elements present on both sides of the equation.

The above equation can be completed by writing as follows,

Al2(SO4)3(aq) + LiOH(aq) Al(OH)3(s) + Li2SO4(aq)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Al2(SO4)3(aq) + LiOH(aq) Al(OH)3(s) + Li2SO4(aq)

Reactant side Atom Product side
2 Al 1
13 O 7
1 H 3
3 S 1
1 Li 2

To balance the above equation, multiply LiOH on the reactant side by six and Al(OH)3 on the product side by two and Li2SO4 by three

Al2(SO4)3(aq) + 6LiOH(aq) 2Al(OH)3(s) + 3Li2SO4(aq)

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
2 Al 2
18 O 18
3 H 6
3 S 3
6 Li 6

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  Al2(SO4)3(aq) + 6LiOH(aq) 2Al(OH)3(s) + 3Li2SO4(aq)

Conclusion

The complete and balanced equation of the given equation is written as:

Al2(SO4)3(aq) + 6LiOH(aq) 2Al(OH)3(s) + 3Li2SO4(aq)

(d)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balancing the equation:

  • There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.
  • Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized.  Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
  • Oxidation reduction and reduction reaction occur simultaneously in same reaction.

To Write: The given equation complete and balanced.

(d)

Expert Solution
Check Mark

Answer to Problem 21.116QP

The complete and balanced equation for the given equation is:

2Al(s) + 6HCl(aq) 3H2(g) + 2AlCl3(aq)

Explanation of Solution

Given Equation:

Al(s) + HCl(aq)

Complete Equation:

A complete equation will have same elements present on both sides of the equation.

The above equation can be completed by writing as follows,

Al(s) + HCl(aq) H2(g) + AlCl3(aq)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Al(s) + HCl(aq) H2(g) + AlCl3(aq)

Reactant side Atom Product side
1 Al 1
1 H 2
1 Cl 3

Multiply Al and HCl on the reactant side by two and six respectively, then multiply H2 and AlCl3 on the product side by three and two respectively.

2Al(s) + 6HCl(aq) 3H2(g) + 2AlCl3(aq)

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
2 Al 2
6 H 6
6 Cl 6

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  2Al(s) + 6HCl(aq) 3H2(g) + 2AlCl3(aq)

Conclusion

The complete and balanced equation of the given equation is written as:

2Al(s) + 6HCl(aq) 3H2(g) + 2AlCl3(aq)

(e)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balancing the equation:

  • There is a Law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical reaction is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.
  • Loss of electron and loss of Hydrogen in a compound is oxidation - the compound is oxidized.  Gain of electron, gain of Oxygen in a compound is reduction - the compound is reduced.
  • Oxidation reduction and reduction reaction occur simultaneously in same reaction.

To Write: The given equation complete and balanced.

(e)

Expert Solution
Check Mark

Answer to Problem 21.116QP

The complete and balanced equation for the given equation is:

Sn(s) + 2HBr(aq) H2(g) + SnBr2(aq)

Explanation of Solution

Given Equation:

Sn(s) + HBr(aq)

Complete Equation:

A complete equation will have same elements present on both sides of the equation.

The above equation can be completed by writing as follows,

Sn(s) + HBr(aq) H2(g) + SnBr2(aq)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Sn(s) + HBr(aq) H2(g) + SnBr2(aq)

Reactant side Atom Product side
1 Sn 1
1 Br 2
1 H 2

Multiply HBr on the reactant side by two.

Sn(s) + 2HBr(aq) H2(g) + SnBr2(aq)

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
1 Sn 1
2 Br 2
2 H 2

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  Sn(s) + 2HBr(aq) H2(g) + SnBr2(aq)

Conclusion

The complete and balanced equation of the given equation is written as:

Sn(s) + 2HBr(aq) H2(g) + SnBr2(aq)

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Chapter 21 Solutions

General Chemistry - Standalone book (MindTap Course List)

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