Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 21, Problem 18P
Estimate the horsepower needed to remove metal at
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Question 4. The following data are available from orthogonal cutting experiments. The depth of
cut (feed) to = 0.13 mm, width of cut b = 2.5 mm, rake angle a = - 5°, and cutting speed V = 2
m/s.
Chip thickness, t. (mm) = 0.23
Cutting force, F. (N) = 430
Thrust force, F; (N) = 280
Determine the shear angle ð, friction coefficient u , shear stress t, shear strain y on the shear
plane, chip velocity Ve, and shear velocity Vs, as well as energies uf ,Ug, and u
17) A50-mm-dia endmill cuts 6061 aluminum with 30% tool engagement at a depth
of 6 mm. The tool rotates at 200 rpm and is feeding at 250 mm/min. There are 2
teeth set at a rake angle of 10°.
a. Calculate the required power of cutting.
b. Determine the spindle torque.
c. Determine the cutting force on each tooth.
d. If the thrust force is measured to be 350N, estimate the tool-chip interface
friction coefficient.
How could you physically verify your power estimate?
i need the answer quickly
Chapter 21 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 21 - Why has the metal-cutting process resisted...Ch. 21 - What variables must be considered in understanding...Ch. 21 - Which of the seven basic chip formation processes...Ch. 21 - How is feed related to speed in the machining...Ch. 21 - Before you select speed and feed for a machining...Ch. 21 - Milling has two feeds. What are they, and which...Ch. 21 - What is the fundamental mechanism of chip...Ch. 21 - What is the difference between oblique machining...Ch. 21 - What are the implications of Figure 21.13, given...Ch. 21 - Note that the units for the approximate equation...
Ch. 21 - For orthogonal machining, the cutting edge radius...Ch. 21 - How do the magnitude of the strain and strain rate...Ch. 21 - Why is titanium such a difficult metal to machine?...Ch. 21 - Explain why you get segmented or discontinuous...Ch. 21 - Why is metal cutting shear stress such an...Ch. 21 - Which of the three cutting forces in oblique...Ch. 21 - How is the energy in a machining process typically...Ch. 21 - Where does the energy consumed in metal cutting...Ch. 21 - What are two ways of estimating the primary...Ch. 21 - What are the three different ways to perform...Ch. 21 - Why does the cutting force Fc increase with...Ch. 21 - Why doesnt the cutting force Fc increase with...Ch. 21 - Prob. 23RQCh. 21 - How does the selection of the machining parameters...Ch. 21 - Suppose you had a machining operation (boring)...Ch. 21 - Make a sketch like that shown in Figure 21.1 with...Ch. 21 - Show how you would do near orthogonal machining in...Ch. 21 - Can you do orthogonal machining on a shaper or...Ch. 21 - What process and material combination would yield...Ch. 21 - What is meant by the statement that machining...Ch. 21 - Prob. 31RQCh. 21 - Figure 21.4 provides suggested cutting speeds and...Ch. 21 - For problem 1, suppose you selected a speed of 145...Ch. 21 - If the cutting forces is 1000 lb calculate the...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - For a turning operation, you have selected a...Ch. 21 - For a slab milling operation using a...Ch. 21 - The power required to machine metal is related to...Ch. 21 - In order to drill a hole in the material described...Ch. 21 - Suppose you have the data in Table 21.A obtained...Ch. 21 - Calculate the horsepower that a process is going...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - Derive equations for F and N using the circular...Ch. 21 - Prob. 14PCh. 21 - Prob. 15PCh. 21 - A manufacturing engineer needs an estimate of the...Ch. 21 - Using Figure 21.4 for input data, determine the...Ch. 21 - Estimate the horsepower needed to remove metal at...Ch. 21 - For a turning process, the horsepower required was...
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- Given that the length of a work-piece made from copper alloy to be face-milled is 250 mm and the width is 25 mm. The cutter diameter is 150 mm and the tooth number is 10. 1. If it takes 20 seconds to perform the cutting, suggest a cutting speed (in mm/s) and a feed (in mm/rev) to be used. 2. Give another set of values of cutting speed (in mm/s) and feed (in mm/rev) that can give the same cutting time as above.arrow_forwardIn turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.arrow_forwardThe following data was obtained from an orthogonal cutting test. Rake angle = 20° Depth of cut = 6 mm Feed rate = 0.25 mm/rev Cutting speed = 0.6 m/s Chip length before cutting = 29.4 mm Vertical cutting force = 1050 N Horizontal cutting force = 630 N Chip length after cutting = 12.9 mm Using Merchant's analysis, calculate (a) Magnitude of resultant force, (b) shear plane angle, (c) friction force and friction angle, and (d) various energies consumed.arrow_forward
- Calculate the machining time to drill four 20 mm diameter holes and one 50 mm diameter central hole in the flange as shown below. Take cutting speed 20 m/min, feed for 20 mm drill 0.2 mm/rev, and for 50 mm drill feed is 0.6 mm/rev, the point angle is 120°? VIVER 20xA 200 D100 SYLON 50arrow_forwardThe tool life equation for HSS tool is VT0.14f 0.7d 0.4 = Constant. The tool life (T) of 20 min is obtained using the following cutting conditions: V = 40 m/min, f = 0.30 mm, d = 2.0 mm If speed (V), feed (f) and depth of cut (d) are increased individually by 25% . Calculate the tool life.arrow_forwardFind the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mmarrow_forward
- A mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 59.6 minutesarrow_forwardA mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 59.6 minutes (a) Find number of passes to finish the entire turning operation ( (b) The actual length of the turning operation in mm ('arrow_forwardIt is required to reduce the thickness of cast iron workpiece with dimensions (L x w x t) of (230 mm x 120 mm x 25 mm) to 22 mm using shaper machine. Given that average cutting speed is 21 m/min, feed 1.2 mm/double stroke, and return/cutting time ratio is 3/4. The approach at each end is 72 mm. If the permissible depth of cut is 2 mm, determine the cutting time in the following cases: i) Using shaper with a mechanically driven ram. ii) Using shaper with a hydraulically driven ram. Solution: i) Mechanically ( ii) Hydraulicallyarrow_forward
- A mild steel specimen of Initial diameter of 51.5 mm is turned to final diameter of 48 mm for an initial length of 151 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.1 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 7 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 48.8 minutes (a) Find number of passes to finish the entire turning operation (b) The actual length of the turning operation in mm ( (c)The time required to complete one single turning operation in minutes (d) Spindle speed in rpmarrow_forwardQ1. Calculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation. Answer Q2. A gray cast iron surface 280 wide and 540mm long may be machined either on a vertical milling machine, using a 100mm - diameter face mill having eight inserted HSS teeth, or on a horizontal milling machine using an HSS slab mill with eight teeth on a 200-mm. diameter. Which machine has the faster cutting time? The values of feed per tooth and cutting speed for both processes are 0.4mm/tooth and 80m/min, respectively. The depth of cut = 3.0 mm and assume A and O equal to 5. Answerarrow_forwardThe outside diameter of a cylinder made of steel is to be turned. The starting diameter is 120 mm and the length is 1400 mm. The feed is 0.3 mm/rev and the depth of cut is 2.5mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.33 and C=500. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time required to complete this turning operation.arrow_forward
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