Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 21, Problem 27RQ
Show how you would do near orthogonal machining in a turning operation like that shown in Figure 21.3. (See Figure 20-11).
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Make a figure and explain how shear plane angle effect the power requirements in the machining. How can you reduce the power requirements during machining in orthogonal cutting?
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Chapter 21 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 21 - Why has the metal-cutting process resisted...Ch. 21 - What variables must be considered in understanding...Ch. 21 - Which of the seven basic chip formation processes...Ch. 21 - How is feed related to speed in the machining...Ch. 21 - Before you select speed and feed for a machining...Ch. 21 - Milling has two feeds. What are they, and which...Ch. 21 - What is the fundamental mechanism of chip...Ch. 21 - What is the difference between oblique machining...Ch. 21 - What are the implications of Figure 21.13, given...Ch. 21 - Note that the units for the approximate equation...
Ch. 21 - For orthogonal machining, the cutting edge radius...Ch. 21 - How do the magnitude of the strain and strain rate...Ch. 21 - Why is titanium such a difficult metal to machine?...Ch. 21 - Explain why you get segmented or discontinuous...Ch. 21 - Why is metal cutting shear stress such an...Ch. 21 - Which of the three cutting forces in oblique...Ch. 21 - How is the energy in a machining process typically...Ch. 21 - Where does the energy consumed in metal cutting...Ch. 21 - What are two ways of estimating the primary...Ch. 21 - What are the three different ways to perform...Ch. 21 - Why does the cutting force Fc increase with...Ch. 21 - Why doesnt the cutting force Fc increase with...Ch. 21 - Prob. 23RQCh. 21 - How does the selection of the machining parameters...Ch. 21 - Suppose you had a machining operation (boring)...Ch. 21 - Make a sketch like that shown in Figure 21.1 with...Ch. 21 - Show how you would do near orthogonal machining in...Ch. 21 - Can you do orthogonal machining on a shaper or...Ch. 21 - What process and material combination would yield...Ch. 21 - What is meant by the statement that machining...Ch. 21 - Prob. 31RQCh. 21 - Figure 21.4 provides suggested cutting speeds and...Ch. 21 - For problem 1, suppose you selected a speed of 145...Ch. 21 - If the cutting forces is 1000 lb calculate the...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - For a turning operation, you have selected a...Ch. 21 - For a slab milling operation using a...Ch. 21 - The power required to machine metal is related to...Ch. 21 - In order to drill a hole in the material described...Ch. 21 - Suppose you have the data in Table 21.A obtained...Ch. 21 - Calculate the horsepower that a process is going...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - Derive equations for F and N using the circular...Ch. 21 - Prob. 14PCh. 21 - Prob. 15PCh. 21 - A manufacturing engineer needs an estimate of the...Ch. 21 - Using Figure 21.4 for input data, determine the...Ch. 21 - Estimate the horsepower needed to remove metal at...Ch. 21 - For a turning process, the horsepower required was...
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- Whats the answer for this please ?arrow_forwardIn turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.arrow_forwardformula and calculationarrow_forward
- Determine the total machining time for a workpiece 30mm in diameter and the required length is 145 mm. Other data: Material: 38mm dia. X 149 mm Depth of cut (turning): 4mm Depth of cut (facing): 2mm Feed : 0.05 mm/rev : 35 SMPM Cutting speedarrow_forwardFind the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mmarrow_forwardProblem 2. Turning Consider Step 2 (Turn Shoulder) in machining the flashlight handle (Figure 2). STEP 1: CUT TO LENGTH STEP 2: TURN SHOULDER 0.600 1.0" 3.000 -0.440 Figure 2. Turning step for Problem 2. i) Calculate the (1) cutting time (in s), (2) the material removal rate (in in3 /s or mm3/s) for this cut, assuming you remove all of the material with one pass (i.e., depth of cut d = (1"-0.6")/2 = 0.2"), and (3) the power (hp or W) required for this turning operation: Consider the following scenarios: Feed (f) in/rev Rotational Speed Cutting Time MRR Power (n) in RPM 0.02 1000 ? ? ? 0.025 900 ? ? ? 0.03 800 ? ? ? 1 j) What changes could you make to the process if you needed to decrease the power requirement?arrow_forward
- Make a figure and explain how shear plane angle effect the power requirements in the machining. How can you reduce the power requirements during machining in orthogonal cutting?arrow_forwardQ3). A block of 190mm length and 100mm width is to be machined in shaping process. The permissible cutting speed is 30m/min. maximum quick return ratio is 3:2 at the design value of stroke of 400mm. Calculate the time of machining of the block, assuming total depth of cut to be 8mm, L=1₂+1+1, 40+190+20=250mm, B=ba+b+bo=10+100+10=120mm?arrow_forward1. In a production turning operation, the cylindrical workpiece is 425 mm long and 190 mm in diameter, Feed 0.30 mm/rev. What cutting speed must be used to achieve a machining time of 7.0 min?arrow_forward
- turning ? How is feed related to speed in machining operations such as Evaluate and Explain.arrow_forwardwhat are the three basic parameters (cutting variables) in the machining process? how to calculate themarrow_forwardFollowing are the data in an orthogonal cutting operation. Rake angle = 15° Cutting speed = 20 m/min Chip thickness = 0.7 mm Width of cut = 4.5 mm Cutting ratio = 0.714 Assuming Merchant's theory, coefficient of friction at the tool-chip interface isarrow_forward
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