Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 21, Problem 8P
In order to drill a hole in the material described in Problem 3 using an HSS drill, you have to select a cutting speed and a feed rate. Using a speed of 105 sfpm for the HSS drill, calculate the rpm for a
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A drilling operation is performed to create a through hole on a steel plate that is 20 mm thick. Cutting speed = 0.4 m/s, and feed = 0.20 mm/rev. The 18-mm-diameter twist drill has a point angle of 120°. Determine the following once the drill reaches full diameter:
a. the machining time and,
b. the metal removal rate
Equation used
Tm
TD₂L
fv
A two-spindle drill cuts two holes at the same time, one 1/2 inch and one 3/4 inch. The workpiece is 1.0 inches thick. Both drills have point angles of 118 degrees and the cutting speed for the material is 300 ft/min. The rotational speed of each drill can be set individually but the feed rate for both holes must be set to the same value because they move together into the material. The feed rate is set so that the total metal removal rate of both drills combined does not exceed 1.50 in3/min. Determine (a) maximum feed rate (in/min) that can be used, (b) individual feeds (in/rev) for each hole, and (c) cutting time for the operation.
A 0.4-inch diameter bit is used in a vertical or vertical drill that operates at 300 rpm. If the feed is 0.005 in / rev, what is the MRR? What is the MRR if the drill diameter is doubled? What is the power required in the drill if the material is an annealed AISI 1080?
Chapter 21 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 21 - Why has the metal-cutting process resisted...Ch. 21 - What variables must be considered in understanding...Ch. 21 - Which of the seven basic chip formation processes...Ch. 21 - How is feed related to speed in the machining...Ch. 21 - Before you select speed and feed for a machining...Ch. 21 - Milling has two feeds. What are they, and which...Ch. 21 - What is the fundamental mechanism of chip...Ch. 21 - What is the difference between oblique machining...Ch. 21 - What are the implications of Figure 21.13, given...Ch. 21 - Note that the units for the approximate equation...
Ch. 21 - For orthogonal machining, the cutting edge radius...Ch. 21 - How do the magnitude of the strain and strain rate...Ch. 21 - Why is titanium such a difficult metal to machine?...Ch. 21 - Explain why you get segmented or discontinuous...Ch. 21 - Why is metal cutting shear stress such an...Ch. 21 - Which of the three cutting forces in oblique...Ch. 21 - How is the energy in a machining process typically...Ch. 21 - Where does the energy consumed in metal cutting...Ch. 21 - What are two ways of estimating the primary...Ch. 21 - What are the three different ways to perform...Ch. 21 - Why does the cutting force Fc increase with...Ch. 21 - Why doesnt the cutting force Fc increase with...Ch. 21 - Prob. 23RQCh. 21 - How does the selection of the machining parameters...Ch. 21 - Suppose you had a machining operation (boring)...Ch. 21 - Make a sketch like that shown in Figure 21.1 with...Ch. 21 - Show how you would do near orthogonal machining in...Ch. 21 - Can you do orthogonal machining on a shaper or...Ch. 21 - What process and material combination would yield...Ch. 21 - What is meant by the statement that machining...Ch. 21 - Prob. 31RQCh. 21 - Figure 21.4 provides suggested cutting speeds and...Ch. 21 - For problem 1, suppose you selected a speed of 145...Ch. 21 - If the cutting forces is 1000 lb calculate the...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - For a turning operation, you have selected a...Ch. 21 - For a slab milling operation using a...Ch. 21 - The power required to machine metal is related to...Ch. 21 - In order to drill a hole in the material described...Ch. 21 - Suppose you have the data in Table 21.A obtained...Ch. 21 - Calculate the horsepower that a process is going...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - Derive equations for F and N using the circular...Ch. 21 - Prob. 14PCh. 21 - Prob. 15PCh. 21 - A manufacturing engineer needs an estimate of the...Ch. 21 - Using Figure 21.4 for input data, determine the...Ch. 21 - Estimate the horsepower needed to remove metal at...Ch. 21 - For a turning process, the horsepower required was...
Additional Engineering Textbook Solutions
Find more solutions based on key concepts
Define a homogeneous material.
Mechanics of Materials (10th Edition)
In each case, determine the internal normal force between lettered points on the bar. Draw all necessary free-b...
Statics and Mechanics of Materials (5th Edition)
Comprehension Check 8-18
A motor with an input power of 100 watts [W] is connected to a flywheel. How long, in ...
Thinking Like an Engineer: An Active Learning Approach (4th Edition)
What is the mass flow rate of dry air flowing at a rate of 5000 ft3/min (2.36 m3/s) where the dry bulb temperat...
Heating Ventilating and Air Conditioning: Analysis and Design
The moment of the force F about an axis extending between A and C.
Engineering Mechanics: Statics & Dynamics (14th Edition)
Determine the normal stress in each member of the truss structure. All joints are ball joint, and the material ...
Introduction To Finite Element Analysis And Design
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 1. Energy required to cut a hole. 2. Energy required for cutting work per second. 3. Maximum fluctuation of energy of the flywheel. 4. Mass of the flywheel having radius of gyration of 1.5 m.arrow_forwardA twin-spindle drill simultaneously drills one ½-in hole and one ¾" through a 1" wide work piece. Both holes are twist drill with 118° point angles. cutting speed for material is 230 ft/min. The rotation speed of each spindle can be configured individually. The feed rate of both holes must be set to the same value, since both spindles go down at the same speed. The forward speed is set in such a way that the speed total metal removal does not exceed 1.50 in3 /min. Determine: a) the velocity maximum feedrate (in/min) that can be used, b) the individual feedrates (in/rev) that result in each hole and c) the time required to drill the holes.arrow_forwardA motorised metal guillotine machine is required to cut 45 mm diameter hole ina plate of 20 mm thickness at rate of 35 holes per minute. It requires a torqueof 7 Nm for an area of hole in mm?. If the cutting takes 1/10 of a second andthe speed of its flywheel varies from 165 rpm to 145 rpm, calculate:1.Energy required to cut a hole.2.Energy required for cutting work per second.3.Maximum fluctuation of energy of the flywheel.4.Mass of the flywheel having radius of gyration of 1.5 m.arrow_forward
- ASAParrow_forwardsolvearrow_forwardA o 20 mm through hole is to be drilled in a 30 mm thick plate using a double fluted, 120° lip angle drill The drill tip is at a distance of 3 mm from the plate surface when cutting is started and an over travel of 2 mm is recommended as a margin to ensure drilling through the full thickness of the plate. If the drill rotates at 500 rev/min and the feed per tooth is 0.01 mm,find the machining time of the operation.arrow_forward
- It takes only 12 seconds to mill 0.5" x 5.5" keyway by means of a 40-tooth cutter at a feed rate of 0.249 mm/tooth. Compute the required speed of the cutter in rpm. 70 O65 O 60 75 Aarrow_forwardThe face milling cutter of D = 200 mm used to cut a block which is 200 mm H, 1=480 mm, if f- 0.7 mm/rev is used and the overrun of the cutter is 12 mm and cutting speed 320 mm/min. Calculate the machining time. Cuttinarrow_forwardA shaper is operated at 120 cutting strokes per minute and is used to machine a work piece of 250 mm in length and 120 mm wide. Use a feed of 0.6 mm per stroke and a depth of cut of 6 mm. Calculate the total machining time to for machining the component. If the forward stroke is completed in 230°, calculate the percentage of the time when the tool is not contacting the work piece.arrow_forward
- Solve First one Onlyarrow_forwardThe outline of the part in the Figure below is to be profile milled using a 20- mm diameter end mill with two teeth. The part is 10 mm thick. The cutting speed = 125 m/min and feed = 0.10 mm/tooth. The part is also to be drilled with a drill size of 10 mm corresponds to T01 with a cutting speed =75 mm/min and feed = 0.08 mm/rev. The two holes pass completely through the part. 30 rad. 125.75 10 dia., 2 holes Write the part program (G & M code program) for the required machining processes. Use absolute programming with the lower left 25 corner of the part as the origin in the x-y axis system. 150 (All dimensions are in mm.) 25 50 75 35 deg.arrow_forwardSolve first Question Only.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Precision Machining Technology (MindTap Course Li...Mechanical EngineeringISBN:9781285444543Author:Peter J. Hoffman, Eric S. Hopewell, Brian JanesPublisher:Cengage Learning
Precision Machining Technology (MindTap Course Li...
Mechanical Engineering
ISBN:9781285444543
Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
Publisher:Cengage Learning
HOME SHOP JIGS & FIXTURES PART 1, TYPES OF JIGS & ACCESSORIES AND THE THEORIE BEHIND THE TOOLS; Author: THATLAZYMACHINIST;https://www.youtube.com/watch?v=EXYqi42JimI;License: Standard Youtube License