Concept explainers
(a)
Interpretation:
Whether the
Concept introduction:
Enantiomers are the compounds that are non-superimposable mirror images of each other.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
Anomers are represented as
(b)
Interpretation:
Whether the D-galactose and L-galactose are diastereomers, enantiomers and/or anomers of each other has to be explained.
Concept introduction:
Enantiomers are the compounds that are non-superimposable mirror images of each other.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
Anomers are represented as
(c)
Interpretation:
Whether the L-allose and D-glucose are diastereomers, enantiomers and/or anomers of each other has to be explained.
Concept introduction:
Enantiomers are the compounds that are non-superimposable mirror images of each other.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
Anomers are represented as
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Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
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- 1) Please list all glycosidic linkages between each monosaccharide units. For example, α(1→4)2) Please discuss whether these oligo/polysaccharides would be reducing or non-reducing sugar. Remember to state your reasoning in complete sentence.arrow_forwardIdentify the component monosaccharides of each of the following compounds and describe the type of glycosidic linkage in each.arrow_forward11.32) Identify the following as properties of either glycogen, amylopectin, both glycogen and amylopectin, or neither glycogen nor amylopectin. a) contains a-(1-6) glycosidic bonds both glycogen and a my lopectin b) contains ß-(1→6) glycosidic bonds neither glycogen nor amylopectin c) contains ß-(1→4) glycosidic bonds neither glycogen nor a mylopectin d) contains glucose and fructose residues only neither glycogen nor amylopectin e) homopolysaccharide both glycogen and a my lo pectin f) heteropolysaccharide neither glycogen nor a mylopectin g) branching occurs less frequently (glycogen or amylopectin) amy lo pectin h) contains helical structures both glycogen and amylopection i) found in plants amy lopectinarrow_forward
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- Indicate the following for each disaccharide: I) type of glycosidic linkage i.e. a(1→4) II) configuration i.e. alpha or beta 1. ОН CH₂OH OH I) II) III) IV) 0 ОН 0 CH₂OH OH ОН OH 2. HO CH₂OH I) II) III) IV) ОН HOCH₂, OH ·0 НО 0 ОНА CH₂OH 3. HO I) II) III) IV) CH OH OH O ОН III) reducing or non-reducing sugar IV) name of each monosaccharide HO CH₂ ОН OH ОН 4. HO I) II) III) IV) CH₂OH 0 OH ОН CH₂OH OH О ОН ОНarrow_forwardWhich of the following is the correct systematic name of the disaccharide shown? α-D-glucopyranosyl-(1→3)-β-D-galactopyranose α-D-gulopyranosyl-(1→4)-β-D-glucopyranose α-D-gulopyranosyl-(1→4)-β-D-galactopyranose α-D-glucopyranosyl-(1→3)-β-D-glucopyranosearrow_forwardFollowing are Fischer projections for a groupof five-carbon sugars, all of which are aldopentoses. Identify thepairs that are enantiomers and the pairs that are epimers. (Thesugars shown here are not all of the possible five-carbon sugars.)arrow_forward
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