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(a)
Interpretation: The relationship between hydrogen, oxygen, and water needs to be identified. Each item needs to be identified as an element, compound, or mixture.
Concept Introduction: An element is a substance that cannot be decomposed further into simpler substances by any chemical process. On the other hand, compounds are composed of two or more elements. They can be decomposed into their elemental components. A mixture in solid, liquid, or gaseous form is said to be homogenous if it has the same proportions of components throughout the sample. Thus, in any homogenous mixture, only one phase of matter is observed. In heterogeneous mixtures, the components of the mixture can be easily identified. There is more than one phase that can be seen by the naked eye. It has a non-uniform composition.
(a)
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Explanation of Solution
The given items are hydrogen, oxygen, and water. Here, water is made up of hydrogen and oxygen combined in a 2:1 ratio. In all the samples of water, hydrogen and oxygen are present in a fixed ratio by mass which is 2 mol of hydrogen and 1 mol of oxygen. Here, hydrogen and oxygen are elements, but water is a compound.
(b)
Interpretation: The relationship between nitrogen, oxygen, and air needs to be identified. Each item needs to be identified as an element, compound, or mixture.
Concept Introduction: An element is a substance that cannot be decomposed further into simpler substances by any chemical process. On the other hand, compounds are composed of two or more elements. They can be decomposed into their elemental components. A mixture in solid, liquid, or gaseous form is said to be homogenous if it has the same proportions of components throughout the sample. Thus, in any homogenous mixture, only one phase of matter is observed. In heterogeneous mixtures, the components of the mixture can be easily identified. There is more than one phase and can be seen by the naked eye. It has a non-uniform composition.
(b)
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Explanation of Solution
The given items are nitrogen, oxygen, and air. Air is composed of gases which include nitrogen and oxygen gas. Air is a mixture of different gases but the major percentage is nitrogen and oxygen gas. The approximate percentages of nitrogen and oxygen gas in the air are 78% and 21% respectively. Here, nitrogen and oxygen are elements, but the air is a homogenous mixture. It is homogenous because all the gases are uniformly distributed.
(c)
Interpretation: The relationship between sodium, chlorine, and table salt needs to be identified. Each item needs to be identified as an element, compound, or mixture.
Concept Introduction: An element is a substance that cannot be decomposed further into simpler substances by any chemical process. On the other hand, compounds are composed of two or more elements. They can be decomposed into their elemental components. A mixture in solid, liquid, or gaseous form is said to be homogenous if it has the same proportions of components throughout the sample. Thus, in any homogenous mixture, only one phase of matter is observed. In heterogeneous mixtures, the components of the mixture can be easily identified. There is more than one phase and can be seen by the naked eye. It has a non-uniform composition.
(c)
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Explanation of Solution
The given items are sodium, chlorine, and table salt. Here, the name and formula for table salt are sodium chloride and NaCl respectively. It is made up of sodium and chlorine combined in a 1:1 ratio. In all the samples of table salt, sodium and chlorine elements are present in a fixed ratio by mass which is 1 mol of sodium and 1 mol of chlorine. Here, sodium and chlorine are elements, but table salt or NaCl is a compound.
(d)
Interpretation: The relationship between carbon, water, and table sugar needs to be identified. Each item needs to be identified as an element, compound, or mixture.
Concept Introduction: An element is a substance that cannot be decomposed further into simpler substances by any chemical process. On the other hand, compounds are composed of two or more elements. They can be decomposed into their elemental components. A mixture in solid, liquid, or gaseous form is said to be homogenous if it has the same proportions of components throughout the sample. Thus, in any homogenous mixture, only one phase of matter is observed. In heterogeneous mixtures, the components of the mixture can be easily identified. There is more than one phase that can be seen by the naked eye. It has a non-uniform composition.
(d)
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Explanation of Solution
The given items are carbon, water, and table sugar. Sugar is a carbohydrate that mainly contains carbon, hydrogen, and oxygen atoms. Here, carbon is an element, water is a compound of hydrogen and oxygen and table sugar is a homogenous mixture as components are uniformly distributed.
Chapter 2 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Solve thisarrow_forwardく Predicting the pr Predict the major products of the following organic reaction: Δ Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. ? Click and drag to start drawing a structure.arrow_forwardpropose synthesisarrow_forward
- Explanation O Conjugated Pi Systems Deducing the reactants of a Diels-Alder reaction Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Xarrow_forwardDiels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forwardHELP! URGENT! PLEASE RESOND ASAP!arrow_forward
- Question 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forwardDetermine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forwardDraw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forward
- Calculate the reaction rate for selenious acid, H2SeO3, if 0.1150 M I-1 decreases to 0.0770 M in 12.0 minutes. H2SeO3(aq) + 6I-1(aq) + 4H+1(aq) ⟶ Se(s) + 2I3-1(aq) + 3H2O(l)arrow_forwardProblem 5-31 Which of the following objects are chiral? (a) A basketball (d) A golf club (b) A fork (c) A wine glass (e) A spiral staircase (f) A snowflake Problem 5-32 Which of the following compounds are chiral? Draw them, and label the chirality centers. (a) 2,4-Dimethylheptane (b) 5-Ethyl-3,3-dimethylheptane (c) cis-1,4-Dichlorocyclohexane Problem 5-33 Draw chiral molecules that meet the following descriptions: (a) A chloroalkane, C5H11Cl (c) An alkene, C6H12 (b) An alcohol, C6H140 (d) An alkane, C8H18 Problem 5-36 Erythronolide B is the biological precursor of erythromycin, a broad-spectrum antibiotic. How H3C CH3 many chirality centers does erythronolide B have? OH Identify them. H3C -CH3 OH Erythronolide B H3C. H3C. OH OH CH3arrow_forwardPLEASE HELP! URGENT! PLEASE RESPOND!arrow_forward
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