(a)
Interpretation: The physical state of gold at room temperature needs to be determined.
Concept Introduction: There are generally three
Gold is solid at room temperature.
Gold is a metal. They are generally solid at room temperature. Also, the melting point of gold is
Therefore, the physical state of gold at room temperature is solid.
(b)
Interpretation: The physical state of gasoline at room temperature needs to be determined.
Concept Introduction: There are generally three states of matter that is solid, liquid and gas. Substances that are solid at room temperature have high melting and boiling points. Melting point is defined as the temperature at which a solid substance starts melting. The boiling point is defined as the temperature of a liquid when its vapor pressure is equal to the atmospheric pressure. This is the temperature when liquid starts boiling and converts into vapor.
Gasoline is liquid at room temperature.
Gasoline is a fuel that is generally composed of crude oil and other petroleum liquids. The boiling point is around
(c)
Interpretation: The physical state of oxygen at room temperature needs to be determined.
Concept Introduction: There are generally three states of matter that is solid, liquid and gas. Substances that are solid at room temperature have high melting and boiling points. Melting point is defined as the temperature at which a solid substance starts melting. The boiling point is defined as the temperature of a liquid when its vapor pressure is equal to the atmospheric pressure. This is the temperature when liquid starts boiling and converts into vapor.
Oxygen is gas at room temperature.
Oxygen is a non-metal. Non-metals are generally gases. Here, the boiling point of oxygen is
(d)
Interpretation: The physical state of neon at room temperature needs to be determined.
Concept Introduction: There are generally three states of matter that is solid, liquid and gas. Substances that are solid at room temperature have high melting and boiling points. Melting point is defined as the temperature at which a solid substance starts melting. The boiling point is defined as the temperature of a liquid when its vapor pressure is equal to the atmospheric pressure. This is the temperature when liquid starts boiling and converts into vapor.
Neon is gas at room temperature.
Neon is a noble gas. The melting point and boiling point of neon is
(e)
Interpretation: The physical state of olive oil at room temperature needs to be determined.
Concept Introduction: There are generally three states of matter that is solid, liquid and gas. Substances that are solid at room temperature have high melting and boiling points. Melting point is defined as the temperature at which a solid substance starts melting. The boiling point is defined as the temperature of a liquid when its vapor pressure is equal to the atmospheric pressure. This is the temperature when liquid starts boiling and converts into vapor.
Olive oil is liquid at room temperature.
The boiling point of olive oil is around
(f)
Interpretation: The physical state of sulfur at room temperature needs to be determined.
Concept Introduction: There are generally three states of matter that is solid, liquid and gas. Substances that are solid at room temperature have high melting and boiling points. Melting point is defined as the temperature at which a solid substance starts melting. The boiling point is defined as the temperature of a liquid when its vapor pressure is equal to the atmospheric pressure. This is the temperature when liquid starts boiling and converts into vapor.
Sulphur is solid at room temperature.
Sulphur is a non-metal. The melting point of sulphur is
(g)
Interpretation: The physical state of mercury at room temperature needs to be determined.
Concept Introduction: There are generally three states of matter that is solid, liquid and gas. Substances that are solid at room temperature have high melting and boiling points. Melting point is defined as the temperature at which a solid substance starts melting. The boiling point is defined as the temperature of a liquid when its vapor pressure is equal to the atmospheric pressure. This is the temperature when liquid starts boiling and converts into vapor.
Mercury is liquid at room temperature.
The melting and boiling point of mercury is
Chapter 2 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below. Find the following: (a) The no. of protons corresponding to each signal in the spectra (6) Give the structure of the compound and assign the signals to each proton in the compound. a 70.2 Integration Values C5H10O2 b 47.7 C 46.5 d 69.5 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 Chemical Shift (ppm) 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8arrow_forwardPart 111. 1 H-NMR spectrum of a compound with integration values in red is given below. Answer the following: (a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure of the molecule below. (b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible. complex splitting patterns assuming J values are not similar. там Br 22 2 3 6 4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0 Chemical Shift (ppm) ra. Br 2 3 6 6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 Chemical Shift (ppm) 2 2 Br 7.3 7.2 7.1 7.0 6.9 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0 Chemical Shift (ppm) 5.9 5.8 5.7 5.5 5.4 5.3 5.2 5.0 4.9arrow_forward1600° 1538°C 1493°C In the diagram, the letter L indicates that it is a liquid. Indicate its components in the upper region where only L is indicated. The iron-iron carbide phase diagram. Temperature (°C) 1400 8 1394°C y+L 1200 2.14 y, Austenite 10000 912°C 800a 0.76 0.022 600 400 (Fe) a, Ferrite Composition (at% C) 15 1147°C a + Fe3C 2 3 Composition (wt% C) L 2500 4.30 2000 y + Fe3C 727°C 1500 Cementite (Fe3C) 1000 4 5 6 6.70 Temperature (°F)arrow_forward
- Nonearrow_forwardPart II. Given below are the 'H-NMR spectrum at 300 MHz in CDC13 and mass spectrum using electron ionization of compound Brian. The FTIR of the said compound showed a strong peak at 1710 cm"). Determine the following: (a) molecular Formula and Degree of unsaturation of compound Brian (b) Basing on the given H-NMR spectrum tabulate the following (i) chemical shifts (ii) integration, ciii) multiplicity and (iv) interferences made for each signal (c) Draw the structure of compound Brian. ) ΕΙ 43 41 27 71 114 (M+) Hmmm 20 30 40 50 60 70 80 90 100 110 120 1H NMR spectrum 300 MHz in CDCl3 2.0 alle 1.0arrow_forwardThe iron-iron carbide phase diagram. In the diagram, the letter L indicates that it is a liquid. Indicate what its components are. Temperature (°C) 1600 10 Composition (at% C) 15 25 1538°C -1493°C 8 1400 1200 1394°C y+L L 2500 1147°C y. Austenite 2.14 4.30 2000 1000 912°C y + Fe3C 800ㅏ 0.76 0.022 600 a, Ferrite a + Fe3C 400 0 (Fe) Composition (wt% C) 727°C 1500 Cementite (Fe3C) 1000 6 6.70 Temperature (°F)arrow_forward
- Part V. Choose which isomer would give the 1H-NMR spectrum below. Justify your reasoning by assigning important signals to the Corresponding protons of the correct molecule. A D on of of of H H 88 2 90 7.8 7.6 7.4 80 5 6 [ppm] 7.2 6.8 6.6 6.4 ō [ppm]arrow_forwardShow work with explanation. don't give Ai generated solutionarrow_forwardQ7. a. Draw the line-bond structure of the major product for the following reaction, if a reaction occurs, assume monohalogenation. b. Calculate the product ratios using the following information (hint: use the number of hydrogens in each category present to calculate the ratios). Chlorination: 1° Reactivity=1 2° Reactivity=4 Heat + Cl2 3° Reactivity=5arrow_forward
- Please correct answer and don't use hand rating and don't use Ai solutionarrow_forwardQ10: Alkane halogenation a. Give the name and structures of the five isomeric hexanes. Page 4 of 5 Chem 0310 Organic Chemistry 1 Recitations b. For each isomer, give all the free radical monochlorination and monobromination products that are structurally isomeric.arrow_forwardQ9. The insecticide DDT (in the box below) is useful in controlling mosquito populations and has low toxicity to humans, but is dangerous to birds and fish. Hoping to alleviate the dangers, little Johnny Whizbang, an aspiring chemist, proposes a new version of DDT ("Bromo-DDT") and shows his synthesis to his boss. Will Johnny Whizbang's synthesis work? Or will he be fired? Assume there is an excess of bromine and polybrominated products can be separated. Explain why. CH3 Br2, light CBR3 ok-ok Br Br Br Br CI "Bromo-DDT" CCl 3 DDT (dichlorodiphenyltrichloroethane) CIarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY