EBK CONCEPTS OF PROGRAMMING LANGUAGES
12th Edition
ISBN: 9780135102251
Author: Sebesta
Publisher: VST
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Chapter 2, Problem 4PS
Explanation of Solution
Comparison on Fortran 0 with Laning and Zierler system:
- The first algebraic translation system, Laning and Zierler system was developed by Laning and Zierler in 1954.
- Fortran 0 was the first compiled high-level language developed in IBM for its system 704, depending upon John Backus and his team’s report titled IMB’s Mathematical Formula translating system.
- Both Fortran 0 and Laning Zierler were mainly used for mathematical computations.
- The Laning Zierler system accepts input in simple algebraic language or notations.
- Unformatted I/O statements are available in Fortran 0.
- Laning Zierler system allows nested parentheses, uses superscripts to indicate exponents.
- Fortran uses E for representing exponents and also uses “D” to specify double precision numbers...
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Students have asked these similar questions
1. Create a Book record that implements the Comparable interface, comparing the
Book objects by year
- title: String
>
- author: String
- year: int
Book
+ compareTo(other Book: Book): int
+ toString(): String
Submit your source code on Canvas (Copy
your code to text box or upload.java file)
>
Comparable
2. Create a main method in Book record.
1) In the main method, create an array of 2 objects of Book with your choice of
title, author, and year.
2) Sort the array by year
3) Print the object. Override the toString in Book to match the example output:
@Javadoc Declaration Console X Properties
Book [Java Application] /Users/kuan/.p2/pool/plugins/org.eclipse.justj.openjdk.hotspo
[Book: year=1901, Book: year=2010]
Q5-The efficiency of a 200 KVA, single phase transformer is 98% when operating at full load 0.8
lagging p.f. the iron losses in the transformer is 2000 watt. Calculate the i) Full load copper losses ii)
half load copper losses and efficiency at half load. Ans: 1265.306 watt, 97.186%
2. Consider the following pseudocode for partition:
function partition (A,L,R)
pivotkey = A [R]
t = L
for i
L to R-1 inclusive:
if A[i] A[i]
t = t + 1
end if
end for
A [t] A[R]
return t
end function
Suppose we call partition (A,0,5) on A=[10,1,9,2,8,5]. Show the state of the list at the
indicated instances.
Initial A
After i=0 ends
After 1 ends
After i 2 ends
After i = 3 ends
After i = 4 ends
After final swap
10 19 285
[12 pts]
Chapter 2 Solutions
EBK CONCEPTS OF PROGRAMMING LANGUAGES
Ch. 2 - In what year was Plankalkl designed? In what year...Ch. 2 - What two common data structures were included in...Ch. 2 - How were the pseudocodes of the early 1950s...Ch. 2 - Speedcoding was invented to overcome two...Ch. 2 - Prob. 5RQCh. 2 - Prob. 6RQCh. 2 - Prob. 7RQCh. 2 - Prob. 8RQCh. 2 - Prob. 9RQCh. 2 - Prob. 10RQ
Ch. 2 - Prob. 11RQCh. 2 - Prob. 12RQCh. 2 - Prob. 13RQCh. 2 - Prob. 14RQCh. 2 - Prob. 15RQCh. 2 - Prob. 16RQCh. 2 - Prob. 17RQCh. 2 - Prob. 18RQCh. 2 - Prob. 19RQCh. 2 - Prob. 20RQCh. 2 - Prob. 21RQCh. 2 - On what programming language was COBOL based?Ch. 2 - In what year did the COBOL design process begin?Ch. 2 - What data structure that appeared in COBOL...Ch. 2 - What organization was most responsible for the...Ch. 2 - Prob. 26RQCh. 2 - Prob. 27RQCh. 2 - Prob. 28RQCh. 2 - Prob. 29RQCh. 2 - Prob. 30RQCh. 2 - Prob. 31RQCh. 2 - Prob. 32RQCh. 2 - Prob. 33RQCh. 2 - Prob. 34RQCh. 2 - Prob. 35RQCh. 2 - Prob. 36RQCh. 2 - Prob. 37RQCh. 2 - Prob. 38RQCh. 2 - Prob. 39RQCh. 2 - What Ada construct provides support for abstract...Ch. 2 - What populates the Smalltalk world?Ch. 2 - Prob. 42RQCh. 2 - Prob. 43RQCh. 2 - Prob. 44RQCh. 2 - What do the Ada and COBOL languages have in...Ch. 2 - What was the first application for Java?Ch. 2 - Prob. 47RQCh. 2 - How does the typing system of PHP and JavaScript...Ch. 2 - Prob. 49RQCh. 2 - Prob. 50RQCh. 2 - Prob. 51RQCh. 2 - Prob. 52RQCh. 2 - Prob. 53RQCh. 2 - What data structure does Python use in place of...Ch. 2 - Prob. 55RQCh. 2 - What characteristic of Rubys arithmetic operators...Ch. 2 - Prob. 57RQCh. 2 - Prob. 58RQCh. 2 - Prob. 59RQCh. 2 - Prob. 60RQCh. 2 - Prob. 61RQCh. 2 - Prob. 62RQCh. 2 - Prob. 63RQCh. 2 - Prob. 1PSCh. 2 - Prob. 2PSCh. 2 - Prob. 3PSCh. 2 - Prob. 4PSCh. 2 - Prob. 5PSCh. 2 - Prob. 6PSCh. 2 - Prob. 7PSCh. 2 - Prob. 8PSCh. 2 - Prob. 9PSCh. 2 - Prob. 10PSCh. 2 - Prob. 11PSCh. 2 - Prob. 12PSCh. 2 - Prob. 13PSCh. 2 - Prob. 14PSCh. 2 - Prob. 15PSCh. 2 - Prob. 16PSCh. 2 - Prob. 17PSCh. 2 - Prob. 18PSCh. 2 - Prob. 19PSCh. 2 - Prob. 20PSCh. 2 - Prob. 21PSCh. 2 - Prob. 22PSCh. 2 - Prob. 23PSCh. 2 - Prob. 24PS
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