
Concept explainers
(a)
The height gained by the baseball
(a)

Answer to Problem 36P
24.7 m.
Explanation of Solution
Given:
Initial velocity of the baseball =vi=22ms
Final velocity of the baseball at the highest point =vf=0ms
Acceleration experienced by baseball = acceleration due to gravity =a=−9.8ms2
Height gained by the ball =h
Displacement of the ball =Δy=h
Formula Used:
Displacement of an object in uniform accelerated motion is given as
Δy=v2f−v2i2aWhere vf and vi are final and initial velocity of the object and a is the acceleration
Calculation:
Consider the motion of the baseball in vertical direction.
Displacement of the baseball is given as
Δy=v2f−v2i2a
Substituting the values
Δy=02−2222(−9.8)=24.69 mΔy≈24.7m
Conclusion:
Therefore, height gained is 24.7 m.
(b)
The time spent by the baseball in air
(b)

Answer to Problem 36P
4.5 seconds.
Explanation of Solution
Given:
Initial velocity of the baseball =vi=22ms
Acceleration experienced by baseball = acceleration due to gravity =a=−9.8ms2
Time of travel =t
Displacement of the ball as it comes back to its starting location =Δy=0m
Formula Used:
Displacement of an object in uniform accelerated motion is given as
Δy=vit+(0.5)at2where vi= initial velocityΔy=displacementt=timea=acceleration
Calculation:
Consider the motion of the baseball in vertical direction.
Substituting the values, to find the time.
0=22t+(0.5)(−9.8)t2t=4.5s
Conclusion:
Therefore, time spent by baseball in air is 4.5 seconds.
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Physics: Principles with Applications
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