Chapter 2, Problem 74GP

To determine

The average acceleration of the ball

Answer to Problem 74GP

  $276.6\frac{\text{m}}{{\text{s}}^{\text{2}}}$

Explanation of Solution

Given:

Initial velocity of the baseball $=v_o=0\frac{\text{m}}{\text{s}}$

Final velocity of the baseball $=v_o=44\frac{\text{m}}{\text{s}}$

Displacement of the ball $=\Delta x=3.5\text{m}$

Average acceleration of the ball $=a$

Formula Used:

Average acceleration is given as

  $a=\frac{v_f^2-v_o^2}{2\Delta x}$

Calculation:

Average acceleration of the ball is given as

  $a=\frac{v_f^2-v_o^2}{2\Delta x}$

Substituting the values

  $\begin{array}{l}a=\frac{{44}^2-0^2}{2(3.5)}\\ a=276.6\frac{\text{m}}{{\text{s}}^{\text{2}}}\end{array}$

Conclusion:

Therefore, average acceleration of the ball is $276.6\frac{\text{m}}{{\text{s}}^{\text{2}}}$