Chapter 2, Problem 10P

(a)

To determine

To Calculate: The average speed of horse.

Explanation of Solution

Given:

Total Distance, $d=\text{116}\text{m +116}\text{m = 232 m}$

Time, $t=\text{14}\text{.0}\text{s + 4}\text{.8}\text{s}=18.8\text{s}$

Formula Used:

Average speed, $v_{avg}=\frac{d}{t}$

Here, d is the total distance covered and t is the total time.

Calculations:

Substitute the values and solve:

  $\begin{array}{c}{v}_{avg}=\frac{d}{t}\\ =\frac{\text{232}\text{m}}{\text{18}\text{.8}\text{s}}\\ \text{=12}\text{.34}\text{m/s}\end{array}$

Conclusion: 

Thus, the average speed of horse is about $\text{12}\text{.34}\text{m/s}$ .

(b)

To determine

To Calculate: The average velocity of horse.

Explanation of Solution

Given:

Displacement, $D=\text{116}\text{m -116}\text{m = 0}$

Time, $t=\text{14}\text{.0}\text{s + 4}\text{.8}\text{s}=18.8\text{s}$

Formula Used:

Average velocity, $V_{avg}=\frac{D}{t}$

Here, D is the displacement and tis the total time.

Calculations:

Substitute the values and solve:

  $\begin{array}{c}{V}_{avg}=\frac{D}{t}\\ =\frac{\text{0}}{\text{18}\text{.8}\text{s}}\\ \text{=}\text{0}\end{array}$

Conclusion: 

As the net displacement is zero, the average velocity of entire trip is also zero.