Chapter 2, Problem 22P

To determine

The acceleration of car.

Answer to Problem 22P

The acceleration of car will be $a=-3.1{\text{ m/s}}^2$

Explanation of Solution

Given data:

Initial velocity: $23\text{ m/s}$

Final velocity: $0\text{ m/s}$

Distance: $85\text{ m/s}$

Formula used:

Second equation of motion

  $v^2-u^2=2as$

Calculation:

Second equation of motion

  $\begin{array}{l}{v}^2-u^2=2as\\ 0-{23}^2=2\times 85a\\ a=-3.1{\text{ m/s}}^2\end{array}$

Conclusion:

There will be retardation of $a=-3.1{\text{ m/s}}^2$