Concept explainers
Videos
(a)
To identify: Whether there is any instant at which the two bicycles have the same velocity.
(a)
Answer to Problem 85GP
Yes, there is one point where the two bicycles have the same velocity. It is when the slopes of both the functions are parallel.
Explanation of Solution
Given:
The given position-time for two bicycles is shown below.
Formula used:
The slope of a function in a position time graph provides the velocity of the moving object.
Calculation:
Consider the given graph. Slopes of parallel lines are equal. B is a straight line, so it will have a constant slope. A is a curve, hence its slope varies while moving from bottom to top. At the point of maximum curvature, A’s slope is the same as B. At this instant, both A and B have the same velocity.
Conclusion:
Therefore, for the given graph there is a point when velocity of both the bicycles is same.
(b)
The bicycle that will have larger acceleration.
(b)
Answer to Problem 85GP
Bicycle A has a larger acceleration.
Explanation of Solution
Given:
The given position-time for two bicycles is shown below.
Formula used:
The slope of a function in a position time graph is the velocity of the moving object.
Calculation:
Bicycle B depicts a straight line in the position time graph. Hence its slope is constant. Since the slope is constant, the acceleration is 0. Bicycle A is represented by a curve, which means that its slope, and hence its velocity changes. From the graph, it is evident that the slope keeps increasing.
Conclusion:
Therefore, bicycle A has a larger acceleration
(c)
The instants at which the bicycles passing each other. Also, the bicycle that will pass the another bicycle.
(c)
Answer to Problem 85GP
At the points of intersections in the graph, the bicycles pass each other. First bicycle B will pass bicycle A and then bicycle A will pass bicycle B.
Explanation of Solution
Given:
The given position-time for two bicycles is shown below.
Calculation:
The graph plots position against time. Thus, it shows the position of an object at different instances of time. If the functions for A and B intersect, then, it means that both A and B are at the same position at that particular instant. Therefore, the bicycles have to pass each other at points of intersections.
From the given graph, it is observed that at the first intersection point bicycle B will pass bicycle but later on at the second point of intersection, bicycle A will pass bicycle B.
Conclusion:
Therefore, both bicycles will meet at point of intersection and will pass each other.
(d)
The bicycle that will have the highest instantaneous velocity.
(d)
Answer to Problem 85GP
Before the instant of time where their velocities are equal, bicycle B has the higher instantaneous velocity after which Bicycle A has the higher velocity.
Explanation of Solution
Given:
The given position-time for two bicycles is shown below.
Formula used:
The slope at particular point of position time graph defines the instantaneous velocity of a moving object.
Calculation:
The slope at a point in the position-time graph gives the velocity of the bicycle at that instant. bicycle B has constant slope since it is a straight line. The slope of the curve representing bicycle A shows an increase from bottom to top. Thus, till the instant where the slopes are equal, bicycle B has a higher instantaneous velocity. After this point, bicycle A, whose slope keeps increasing will have a higher instantaneous velocity.
Conclusion:
Therefore, bicycle B will have greatest instantaneous velocity and then later on A will have greatest velocity.
(e)
The bicycle that will have higher average velocity.
(e)
Answer to Problem 85GP
Both the bicycles must havethe same average velocity.
Explanation of Solution
Given:
The given position-time for two bicycles is shown below.
Formula used:
The slope of a function in a position time graph is the velocity of the moving object. The average velocity is the ratio of total displacement and total time taken
Calculation:
Bicycle B is depicted by a straight line. Its velocity is constant. For A, the displacement is lesser but the total time taken is also lesser. So, the average velocity for both the bicycles A and B should have almost the same value.
Conclusion:
Therefore, both bicycles will have same average velocity.
Chapter 2 Solutions
Physics: Principles with Applications
Additional Science Textbook Solutions
Campbell Biology in Focus (2nd Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Introductory Chemistry (6th Edition)
College Physics: A Strategic Approach (3rd Edition)
Applications and Investigations in Earth Science (9th Edition)
Organic Chemistry (8th Edition)
- A piece of metal is placed on top of a 2.0 - kg wooden block (mass density = 562 kg/m³) piece. UseArchimedes' principle to calculate the mass (in kg) of copper if the top of the wood surface is exactly at thewater's surface?arrow_forwardA filmmaker wants to achieve an interesting visual effect by filming a scene through a converging lens with a focal length of 50.0 m. The lens is placed betwen the camera and a horse, which canters toward the camera at a constant speed of 7.9 m/s. The camera starts rolling when the horse is 36.0 m from the lens. Find the average speed of the image of the horse (a) during the first 2.0 s after the camera starts rolling and (b) during the following 2.0 s.arrow_forwardAnswer the question (Physics)arrow_forward
- Hi! I need help with these calculations for part i and part k for a physics Diffraction Lab. We used a slit width 0.4 mm to measure our pattern.arrow_forwardExamine the data and % error values in Data Table 3 where the angular displacement of the simple pendulum decreased but the mass of the pendulum bob and the length of the pendulum remained constant. Describe whether or not your data shows that the period of the pendulum depends on the angular displacement of the pendulum bob, to within a reasonable percent error.arrow_forwardIn addition to the anyalysis of the graph, show mathematically that the slope of that line is 2π/√g . Using the slope of your line calculate the value of g and compare it to 9.8.arrow_forward
- An object is placed 24.1 cm to the left of a diverging lens (f = -6.51 cm). A concave mirror (f= 14.8 cm) is placed 30.2 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?arrow_forwardConcept Simulation 26.4 provides the option of exploring the ray diagram that applies to this problem. The distance between an object and its image formed by a diverging lens is 5.90 cm. The focal length of the lens is -2.60 cm. Find (a) the image distance and (b) the object distance.arrow_forwardPls help ASAParrow_forward
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSON
Introduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Lecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON