Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 2, Problem 85GP

(a)

To determine

To identify: Whether there is any instant at which the two bicycles have the same velocity.

(a)

Expert Solution
Check Mark

Answer to Problem 85GP

Yes, there is one point where the two bicycles have the same velocity. It is when the slopes of both the functions are parallel.

Explanation of Solution

Given:

The given position-time for two bicycles is shown below.

  Physics: Principles with Applications, Chapter 2, Problem 85GP , additional homework tip  1

Formula used:

The slope of a function in a position time graph provides the velocity of the moving object.

Calculation:

Consider the given graph. Slopes of parallel lines are equal. B is a straight line, so it will have a constant slope. A is a curve, hence its slope varies while moving from bottom to top. At the point of maximum curvature, A’s slope is the same as B. At this instant, both A and B have the same velocity.

Conclusion:

Therefore, for the given graph there is a point when velocity of both the bicycles is same.

(b)

To determine

The bicycle that will have larger acceleration.

(b)

Expert Solution
Check Mark

Answer to Problem 85GP

Bicycle A has a larger acceleration.

Explanation of Solution

Given:

The given position-time for two bicycles is shown below.

  Physics: Principles with Applications, Chapter 2, Problem 85GP , additional homework tip  2

Formula used:

The slope of a function in a position time graph is the velocity of the moving object.

Calculation:

Bicycle B depicts a straight line in the position time graph. Hence its slope is constant. Since the slope is constant, the acceleration is 0. Bicycle A is represented by a curve, which means that its slope, and hence its velocity changes. From the graph, it is evident that the slope keeps increasing.

Conclusion:

Therefore, bicycle A has a larger acceleration

(c)

To determine

The instants at which the bicycles passing each other. Also, the bicycle that will pass the another bicycle.

(c)

Expert Solution
Check Mark

Answer to Problem 85GP

At the points of intersections in the graph, the bicycles pass each other. First bicycle B will pass bicycle A and then bicycle A will pass bicycle B.

Explanation of Solution

Given:

The given position-time for two bicycles is shown below.

  Physics: Principles with Applications, Chapter 2, Problem 85GP , additional homework tip  3

Calculation:

The graph plots position against time. Thus, it shows the position of an object at different instances of time. If the functions for A and B intersect, then, it means that both A and B are at the same position at that particular instant. Therefore, the bicycles have to pass each other at points of intersections.

From the given graph, it is observed that at the first intersection point bicycle B will pass bicycle but later on at the second point of intersection, bicycle A will pass bicycle B.

Conclusion:

Therefore, both bicycles will meet at point of intersection and will pass each other.

(d)

To determine

The bicycle that will have the highest instantaneous velocity.

(d)

Expert Solution
Check Mark

Answer to Problem 85GP

Before the instant of time where their velocities are equal, bicycle B has the higher instantaneous velocity after which Bicycle A has the higher velocity.

Explanation of Solution

Given:

The given position-time for two bicycles is shown below.

  Physics: Principles with Applications, Chapter 2, Problem 85GP , additional homework tip  4

Formula used:

The slope at particular point of position time graph defines the instantaneous velocity of a moving object.

Calculation:

The slope at a point in the position-time graph gives the velocity of the bicycle at that instant. bicycle B has constant slope since it is a straight line. The slope of the curve representing bicycle A shows an increase from bottom to top. Thus, till the instant where the slopes are equal, bicycle B has a higher instantaneous velocity. After this point, bicycle A, whose slope keeps increasing will have a higher instantaneous velocity.

Conclusion:

Therefore, bicycle B will have greatest instantaneous velocity and then later on A will have greatest velocity.

(e)

To determine

The bicycle that will have higher average velocity.

(e)

Expert Solution
Check Mark

Answer to Problem 85GP

Both the bicycles must havethe same average velocity.

Explanation of Solution

Given:

The given position-time for two bicycles is shown below.

  Physics: Principles with Applications, Chapter 2, Problem 85GP , additional homework tip  5

Formula used:

The slope of a function in a position time graph is the velocity of the moving object. The average velocity is the ratio of total displacement and total time taken

Calculation:

Bicycle B is depicted by a straight line. Its velocity is constant. For A, the displacement is lesser but the total time taken is also lesser. So, the average velocity for both the bicycles A and B should have almost the same value.

Conclusion:

Therefore, both bicycles will have same average velocity.

Chapter 2 Solutions

Physics: Principles with Applications

Ch. 2 - Can an object be increasing in speed as its...Ch. 2 - A baseball player hits a ball straight up into the...Ch. 2 - As a freely falling object speeds up, what is...Ch. 2 - Prob. 14QCh. 2 - You travel from point A to point B in a car moving...Ch. 2 - Prob. 16QCh. 2 - Prob. 17QCh. 2 - Prob. 18QCh. 2 - Prob. 19QCh. 2 - Prob. 20QCh. 2 - Describe in words the motion plotted in Fig. 2-32...Ch. 2 - Describe in words the motion of the object graphed...Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - A sports car accelerates from rest to 95 km/h in...Ch. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - 19.(II) A sports car moving at constant velocity...Ch. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57GPCh. 2 - Prob. 58GPCh. 2 - Prob. 59GPCh. 2 - Prob. 60GPCh. 2 - Prob. 61GPCh. 2 - Prob. 62GPCh. 2 - Prob. 63GPCh. 2 - Prob. 64GPCh. 2 - Prob. 65GPCh. 2 - Prob. 66GPCh. 2 - Prob. 67GPCh. 2 - Prob. 68GPCh. 2 - Prob. 69GPCh. 2 - Prob. 70GPCh. 2 - Prob. 71GPCh. 2 - Prob. 72GPCh. 2 - Prob. 73GPCh. 2 - Prob. 74GPCh. 2 - Prob. 75GPCh. 2 - Prob. 76GPCh. 2 - Prob. 77GPCh. 2 - Prob. 78GPCh. 2 - Prob. 79GPCh. 2 - Prob. 80GPCh. 2 - Prob. 81GPCh. 2 - Prob. 82GPCh. 2 - Prob. 83GPCh. 2 - Prob. 84GPCh. 2 - Prob. 85GP
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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY