Chapter 2, Problem 54P

(a)

To determine

The distance the object traveled during the first minute.

Answer to Problem 54P

The distance traveled by the object during the first minute is 1700 m.

Explanation of Solution

Given:

Consider the graph shown below.

  

Values might differ slightly, as the calculations are obtained by reading the graph.

Formula Used:

Distance is calculated as $\Delta s=\Delta v\times \Delta t$ . Here total distance can be calculated by measuring the total area under the graph of velocity-time.

Calculation:

As seen in the graph, each block in the velocity-time graph has a total distance equal to $\Delta s=(10\text{m/s)(10s)=100m}$ . A minute is equal to $60\sec$ . In the time interval $t=0\mathrm{s}-60s$ , the total number of blocks by counting and estimating the graph is $17$ . Thus, the total distance covered by the object in the first minute is $17\times 100\text{m}=1700\text{m}$

Conclusion:

Thus, distance covered in the first minute is 1700 m.

(b)

To determine

The distance the object traveled during the second minute.

Answer to Problem 54P

The distance covered in the second minute is 500 m.

Explanation of Solution

Given:

Consider the graph shown below.

  

Values might differ slightly, as the calculations are obtained by reading the graph.

Calculation:

As seen in the graph, each block in the velocity-time graph has a total distance equal to $\Delta s=(10\text{m/s)(10s)=100m}$ . In the time interval $t=61\mathrm{s}-120s$ , the total number of blocks by counting and estimating the graph is $5$ . Thus, the total distance covered by the object in the second minute is $\text{5}\times \text{100m=500m}$

Conclusion:

Thus, distance covered in the second minute is 500m.