Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
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Chapter 2, Problem 56P

(a)

To determine

To identify: Whether the object is moving in positive or negative direction for segment A to B.

(a)

Expert Solution
Check Mark

Answer to Problem 56P

The object is moving in the negative direction.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  1

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

In the graph segment A-B, the object is moving in a negative direction as the slope of the line segment is decreasing over time.

Conclusion:

The object would be moving in the negative direction.

(b)

To determine

To identify: Whether the object is speeding up or slowing down in graph for segment A to B.

(b)

Expert Solution
Check Mark

Answer to Problem 56P

The object is speeding up.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  2

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

In the segment A to B, the object is moving from a less steep position to steeper one, this suggests that the object is speeding up.

Conclusion:

The object is speeding up.

(c)

To determine

To identify: Whether the acceleration of an object is positive or negative for segment A to B.

(c)

Expert Solution
Check Mark

Answer to Problem 56P

The acceleration of the object is negative.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  3

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

During the interval of A to B, the graph is going concave downward i.e. slope is going more negative. Thus, the acceleration is negative.

Conclusion:

The acceleration of the object is negative.

(d)

To determine

To identify: Whether the object is moving in positive or negative direction for segment D to E.

(d)

Expert Solution
Check Mark

Answer to Problem 56P

The object would be moving in a positive direction.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  4

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

For the segment D to E, object’s distance increases with time then the objects moves faster.

In the graph segment D-E, the object is moving in a positive direction as the slope of the line segment is increasing.

Conclusion:

The object would be moving in a positive direction.

(e)

To determine

To identify: Whether the object is speeding up or slowing down for segment D to E.

(e)

Expert Solution
Check Mark

Answer to Problem 56P

The object is speeding up.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  5

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

For the segment D to E, object’s distance increases with time then the objects moves faster.

The object is moving on the graph from a less steep position to steeper that is slope is increasing with time.This suggests that the object is speeding up.

Conclusion:

The object is speeding up.

(f)

To determine

To identify: Whether the acceleration of an object is positive or negative in the graph segment D to E.

(f)

Expert Solution
Check Mark

Answer to Problem 56P

The object will accelerate.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  6

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.For the segment D to E, object’s distance increases with time then the objects moves faster.

During the interval D to E, the graph is going concave upward i.e. slope is going more positive. Thus, the acceleration is positive.

Conclusion:

The object will accelerate.

(g)

To determine

To identify: Whether the object moving in the positive or negative direction in the graph segment C to D.

(g)

Expert Solution
Check Mark

Answer to Problem 56P

The object is not moving in either direction. The object is at rest.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  7

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

For the segment C to D, the object’s distance is constant with time then object remains stationary.

After reading the graph segment C-D, the object is not moving in either direction. Thus, the distance graph is linearly constant.

Conclusion:

The distance between duration of graph segment C-D is constant. Thus, the object will remain at rest.

(h)

To determine

To identify: Whether the object speeding up or slowing down in graph segment C to D.

(h)

Expert Solution
Check Mark

Answer to Problem 56P

The object is not moving in either direction. The object is at rest.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  8

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.

For the segment C to D, the object’s distance is constant with time then object remains stationary.

After reading the graph segment C-D, the object is not moving in either direction. Thus, the velocity of the object is zero.

Conclusion:

The velocity of the object is zero that is the object is at rest.

(i)

To determine

To identify: Whether the acceleration of the object positive or negative in the graph segment C to D.

(i)

Expert Solution
Check Mark

Answer to Problem 56P

The object is not moving in either direction. So, the acceleration is zero.

Explanation of Solution

Introduction:

Consider the given graph as shown below.

  Physics: Principles with Applications, Chapter 2, Problem 56P , additional homework tip  9

For the segment A to B, object is moving constantly and then distance decreases rapidly with time.For the segment C to D, the object’s distance is constant with time then object remains stationary.

After reading the graph segment C-D, the object is not moving in either direction. Thus, the acceleration is zero.

Conclusion:

The object is not moving in either direction. So, the acceleration is zero.

Chapter 2 Solutions

Physics: Principles with Applications

Ch. 2 - Can an object be increasing in speed as its...Ch. 2 - A baseball player hits a ball straight up into the...Ch. 2 - As a freely falling object speeds up, what is...Ch. 2 - Prob. 14QCh. 2 - You travel from point A to point B in a car moving...Ch. 2 - Prob. 16QCh. 2 - Prob. 17QCh. 2 - Prob. 18QCh. 2 - Prob. 19QCh. 2 - Prob. 20QCh. 2 - Describe in words the motion plotted in Fig. 2-32...Ch. 2 - Describe in words the motion of the object graphed...Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - A sports car accelerates from rest to 95 km/h in...Ch. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - 19.(II) A sports car moving at constant velocity...Ch. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57GPCh. 2 - Prob. 58GPCh. 2 - Prob. 59GPCh. 2 - Prob. 60GPCh. 2 - Prob. 61GPCh. 2 - Prob. 62GPCh. 2 - Prob. 63GPCh. 2 - Prob. 64GPCh. 2 - Prob. 65GPCh. 2 - Prob. 66GPCh. 2 - Prob. 67GPCh. 2 - Prob. 68GPCh. 2 - Prob. 69GPCh. 2 - Prob. 70GPCh. 2 - Prob. 71GPCh. 2 - Prob. 72GPCh. 2 - Prob. 73GPCh. 2 - Prob. 74GPCh. 2 - Prob. 75GPCh. 2 - Prob. 76GPCh. 2 - Prob. 77GPCh. 2 - Prob. 78GPCh. 2 - Prob. 79GPCh. 2 - Prob. 80GPCh. 2 - Prob. 81GPCh. 2 - Prob. 82GPCh. 2 - Prob. 83GPCh. 2 - Prob. 84GPCh. 2 - Prob. 85GP
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