Chapter 2, Problem 21Q

Describe in words the motion plotted in Fig. 2-32 in terms of velocity, acceleration, etc. [Hint: First to duplicate the motion plotted by walking or moving your hand.]

To determine

To Describe:

The terms like velocity and acceleration.

Answer to Problem 21Q

Solution:

The velocity of the product is equal to the slope of time $t$

which is proportional to the displacement of the object.

Given:

Explanation of Solution

When the subject start to move from the origin $O$

at 0 s till about 20 s. The velocity is constant as the slope is uniform and hence the acceleration is 0. Thereafter, the object accelerates till about 35 s. Between 35 s to 40 s, the object is at rest as the position is same in this time interval. After 40 s, the object starts deaccelerating as the slope is negative and non-uniform.