Calculate the work performed by a person who exerts a force of 30 N(N = newtons) to move a box 30 meters if the force were (a) exactly parallel to the direction of movement, and (b)45° to the direction of movement. Do the relative magnitudes make sense?

Question

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Answer 1

Textbook Question

Chapter 2, Problem 2.1E

Calculate the work performed by a person who exerts a force of 30 N(N = newtons) to move a box 30 meters if the force were (a) exactly parallel to the direction of movement, and (b)45° to the direction of movement. Do the relative magnitudes make sense?

Expert Solution

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Expert Solution

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work were 45° to the direction of movement = 640 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

degree = 45°

Work = F.s = |F||s| cos Ѳ

Therefore work = 30 N. 30m cos 45°

= 30 x 30 x0.71

Work = 640 J

Conclusion

Thus the work at 45° to the direction of movement = 640 J

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Answer 2

Textbook Question

Chapter 2, Problem 2.1E

Calculate the work performed by a person who exerts a force of 30 N(N = newtons) to move a box 30 meters if the force were (a) exactly parallel to the direction of movement, and (b)45° to the direction of movement. Do the relative magnitudes make sense?

Expert Solution

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Expert Solution

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work were 45° to the direction of movement = 640 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

degree = 45°

Work = F.s = |F||s| cos Ѳ

Therefore work = 30 N. 30m cos 45°

= 30 x 30 x0.71

Work = 640 J

Conclusion

Thus the work at 45° to the direction of movement = 640 J

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 2, Problem 2.1E

Calculate the work performed by a person who exerts a force of 30 N(N = newtons) to move a box 30 meters if the force were (a) exactly parallel to the direction of movement, and (b)45° to the direction of movement. Do the relative magnitudes make sense?

Expert Solution

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Expert Solution

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work were 45° to the direction of movement = 640 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

degree = 45°

Work = F.s = |F||s| cos Ѳ

Therefore work = 30 N. 30m cos 45°

= 30 x 30 x0.71

Work = 640 J

Conclusion

Thus the work at 45° to the direction of movement = 640 J

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 2, Problem 2.1E

Calculate the work performed by a person who exerts a force of 30 N(N = newtons) to move a box 30 meters if the force were (a) exactly parallel to the direction of movement, and (b)45° to the direction of movement. Do the relative magnitudes make sense?

Expert Solution

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Expert Solution

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work were 45° to the direction of movement = 640 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

degree = 45°

Work = F.s = |F||s| cos Ѳ

Therefore work = 30 N. 30m cos 45°

= 30 x 30 x0.71

Work = 640 J

Conclusion

Thus the work at 45° to the direction of movement = 640 J

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Expert Solution

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work were 45° to the direction of movement = 640 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

degree = 45°

Work = F.s = |F||s| cos Ѳ

Therefore work = 30 N. 30m cos 45°

= 30 x 30 x0.71

Work = 640 J

Conclusion

Thus the work at 45° to the direction of movement = 640 J

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were exactly parallel to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer 13

Answer to Problem 2.1E

Work exactly parallel to the direction of movement = 900 J

Answer 14

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

distance = 30m

Work = F.s

Therefore work = 30 N.30 m= 900 J

Answer 15

Conclusion

Thus the Work exactly parallel to the direction of movement = 900 J

Answer 16

Expert Solution

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.

Answer to Problem 2.1E

Work were 45° to the direction of movement = 640 J

Explanation of Solution

The work is defined as force x displacement [distance].

In the given question

work = 30N

degree = 45°

Work = F.s = |F||s| cos Ѳ

Therefore work = 30 N. 30m cos 45°

= 30 x 30 x0.71

Work = 640 J

Conclusion

Thus the work at 45° to the direction of movement = 640 J

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b)

Interpretation

To calculate the work performed by a person who exerts a force of 30N to move a box 30 meters if the force were 45° to the direction of movement.

Concept introduction

The work is performed on an object when an object moves a certain distance s due to the force F. Mathematically, it is indicated by the dot product of the force vector F and the distance vector s. The mathematical equation is given below,

Work = F.s = |F||s| cos Ѳ

Where Ѳ is the angle between the vectors F and s. The unit of work is joules. Work is a way to transfer the energy. The energy is defined as the ability to do work and so energy and work are described using the same unit in joules.