In Example 2.5, we noted that Anna could go wherever she wished in as little time as desired by going fast enough to length−contract the distance to an arbitrarily small value. This overlooks a physiological limitation. Accelerations greater than about 30g are fatal, and there are serious concerns about the effects of prolonged accelerations greater than 1g. Here we see how far a person could go under a constant acceleration of 1g, producing a comfortable artificial gravity. (a) Though traveler Anna accelerates, Bob, being on near−inertial Earth, is a reliable observer and will see less time go by on Anna’s clock ( d t ' ) than on his own ( d t ) . Thus, d t ' = ( 1 / γ u ) d t , where u isAnna’s instantaneous speed relative to Bob, Using the result of Exercise 117(c), with g replacing F / m , substitute for u , then integrate to show that t = c g sinh g t ' c (b) How much time goes by for observes on Earth as they “see” Anna age 20 years? (c) Using the result of Exercise 119, show that when Anna has aged a time t ' . She is a distance fromEarth (according to Earth observers) of x = c 2 g ( cosh g t ' c − 1 ) (d) If Anna accelerates away from Earth while aging 20 years and then slows to a stop while aging another 20, how far away from Earth will she end up, and how much time will have passed on Earth?
In Example 2.5, we noted that Anna could go wherever she wished in as little time as desired by going fast enough to length−contract the distance to an arbitrarily small value. This overlooks a physiological limitation. Accelerations greater than about 30g are fatal, and there are serious concerns about the effects of prolonged accelerations greater than 1g. Here we see how far a person could go under a constant acceleration of 1g, producing a comfortable artificial gravity. (a) Though traveler Anna accelerates, Bob, being on near−inertial Earth, is a reliable observer and will see less time go by on Anna’s clock ( d t ' ) than on his own ( d t ) . Thus, d t ' = ( 1 / γ u ) d t , where u isAnna’s instantaneous speed relative to Bob, Using the result of Exercise 117(c), with g replacing F / m , substitute for u , then integrate to show that t = c g sinh g t ' c (b) How much time goes by for observes on Earth as they “see” Anna age 20 years? (c) Using the result of Exercise 119, show that when Anna has aged a time t ' . She is a distance fromEarth (according to Earth observers) of x = c 2 g ( cosh g t ' c − 1 ) (d) If Anna accelerates away from Earth while aging 20 years and then slows to a stop while aging another 20, how far away from Earth will she end up, and how much time will have passed on Earth?
In Example 2.5, we noted that Anna could go wherever she wished in as little time as desired by going fast enough to length−contract the distance to an arbitrarily small value. This overlooks a physiological limitation. Accelerations greater than about 30g are fatal, and there are serious concerns about the effects of prolonged accelerations greater than 1g. Here we see how far a person could go under a constant acceleration of 1g, producing a comfortable artificial gravity. (a) Though traveler Anna accelerates, Bob, being on near−inertial Earth, is a reliable observer and will see less time go by on Anna’s clock
(
d
t
'
)
than on his own
(
d
t
)
. Thus,
d
t
'
=
(
1
/
γ
u
)
d
t
, where u isAnna’s instantaneous speed relative to Bob, Using the result of Exercise 117(c), with g replacing
F
/
m
, substitute for u, then integrate to show that
t
=
c
g
sinh
g
t
'
c
(b) How much time goes by for observes on Earth as they “see” Anna age 20 years? (c) Using the result of Exercise 119, show that when Anna has aged a time
t
'
. She is a distance fromEarth (according to Earth observers) of
x
=
c
2
g
(
cosh
g
t
'
c
−
1
)
(d) If Anna accelerates away from Earth while aging 20 years and then slows to a stop while aging another 20, how far away from Earth will she end up, and how much time will have passed on Earth?
Joey starts riding his scooter from his apartment to campus. He thinks it would be fun to make a graph ofhis position relative to time. By a weird coincidence, the graph is perfectly modeled by the equation
3t^2 -5t + 6
He tells his friend Andie that his average velocity for the second half of his trip was 39.2 units per timeinterval, because the slope formula says to do
(256 - 60)/(5 -10)
Is Joey correct?
An alien spaceship is 500 m above the ground and moving at a constant velocity of 150 m/s upwards. How high above the ground is the ship after 5 seconds?
Note: Make an illustration too with a complete solution. Do it digitally-not handwritten. Thank you
The moon is about from Earth. Traveling at the speed of light, m/s, how long does it take a laser beam to go from Earth to the Moon and back again? The same physics was responsible for the noticeable delay in communication signals between lunar astronauts and controllers at the Houston Space Flight Center.
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