Explanation Given Data: Displacement of spring = 0.5 m Spring constant = 18 N/m Formula Used: Energy of spring 1 2 k x 2 Δ E = Δ m c 2 Calculation: Energy of the spring: 1 2 k x 2 = 1 2 ( 18N/m ) ( 0.5 m ) 2 = 2.2 5J . According to mass-energy equivalence relation, there will be an increase in mass on an increase in energy

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ISBN: 9780805303087

Author: Randy Harris

Publisher: Addison Wesley

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Relativistic Energy and Momentum

According to classical physics, time flow is the same for every observer. But according to einstein's theory, time flow is different for different observers. The idea that time flow is not the same for all may sound strange because we may not experience …

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Chapter 2, Problem 73E

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To Find: An increase in the mass of spring while compressing it.

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Chapter 2, Problem 72E

Chapter 2, Problem 74E

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An increase in the mass of spring while compressing it.

Solution Summary: The author explains the mass-energy equivalence relation of the spring.

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Chapter 2 Solutions