Explanation Given Data: u x ' = u x − v 1 − u x v c 2 u ′ y = u y γ v ( 1 − u x v c 2 ) u ′ z = u z γ v ( 1 − u x v c 2 ) Formula Used: γ = 1 1 − ( v c ) 2 Calculation: γ u ′ = 1 1 − u 2 c 2 = 1 1 − u ′ x 2 + u ′ y 2 + u ′ z 2 c 2 = 1 1 − 1 c 2 ( ( u x − v ( 1 − u x v / c 2 ) ) 2 + ( u y γ ( 1 − u x v / c 2 ) ) 2 + ( u 2 γ v ( 1 − u x v / c 2 ) ) 2 ) = ( 1 − u x v c 2 ) ( 1 − u x v c 2 ) 2 − 1 c 2 ( ( u x − v ) 2 + u y 2 ( 1 − v 2 c 2 ) + u z <

2nd Edition

ISBN: 9780805303087

Author: Randy Harris

Publisher: Addison Wesley

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Relativistic Energy and Momentum

According to classical physics, time flow is the same for every observer. But according to einstein's theory, time flow is different for different observers. The idea that time flow is not the same for all may sound strange because we may not experience …

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Chapter 2, Problem 67E

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To prove: γu′=(1−uxvc2)γvγu

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Chapter 2, Problem 66E

Chapter 2, Problem 68E

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To prove : γ u ′ = ( 1 − u x v c 2 ) γ v γ u

Solution Summary: The author explains the formula used to prove the value of gamma.

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To prove: γu′=(1−uxvc2)γvγu

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Chapter 2 Solutions