Introduction To Computing Systems
Introduction To Computing Systems
3rd Edition
ISBN: 9781260150537
Author: PATT, Yale N., Patel, Sanjay J.
Publisher: Mcgraw-hill,
Question
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Chapter 2, Problem 10E

a.

Program Plan Intro

Steps to convert binary number into decimal value:

  • If “0” is appeared in the Left most Significant Bit (LSB), it denotes the sign of the decimal value is positive. Binary number can be directly converted into decimal number.
  • The sign of the decimal value is negative, if the LSB is one.
    • If “1” is appeared in the LSB, compute 2’s complement of the decimal value.
    • To find 2’s complement, transform the bits from “0” to “1” and from “1” to “0”, which gives 1’s complement and then add “1” to the result.
  • Decimal value can be obtained by adding the powers of “2”, which having the coefficients “1”.
  • The user includes a minus sign in front of the decimal value, if the original number is negative.

b.

Explanation of Solution

Conversion from the binary number “01011010” to decimal value:

  • The LSB of the binary number is “0” and it represents the sign of the decimal value is positive.
  • Hence, the user can directly compute the magnitude value as follows,

27×0+26×1+25×0+24×1

c.

Explanation of Solution

Conversion from the binary number “11111110” to decimal value:

  • The LSB of the binary number is “1” and it represents the sign of the decimal value is negative.
  • The user should find the 2’s complement representation as follows,
    • Find the 1’s complement by transforming the bits from “0” to “1” and from “1” to “0”.
    • Hence, the 1’s complement of the number is ‘00000001”.
    • Add “1” to the above result. “00000001+1”, which gives “00000010”.
  • The 2’s complement representation of the positive number is “00000010”...

d.

Explanation of Solution

Conversion from the binary number “0011100111010011” to decimal value:

  • The LSB of the binary number is “0” and it represents the sign of the decimal value is positive.
  • Hence, the user can directly compute the magnitude value as follows,

215×0+214×0+213×1+212×1+211×1+210×0+29×0+28×1+27×1+26×1+2

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