The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn. Concept Introduction: The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized. The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH 2 OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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Answer 1

Question

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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Answer 2

Question

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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Answer 3

Question

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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Answer 4

Question

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

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Answer 5

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

Answer 6

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

Answer 7

Chapter 19, Problem 31P

Interpretation Introduction

Interpretation:

The structures of Ribitol, ß-D-ribose 1-phosphate and D-ribose should be drawn.

Concept Introduction:

The sodium borohydride is a reducing agent, so it reduces the functional group present in the carbohydrate and itself get oxidized.

The reduction of aldehyde results in the formation of alcohol because reduction can also be defined as addition of hydrogen atom thus, -CHO group becomes -CH₂ OH after addition of two hydrogen atoms on carbonyl carbon of the aldehydic group.

Answer 8

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Answer 11

Ch. 19.1 - Prob. 19.1QC Ch. 19.1 - Prob. 19.2QC Ch. 19.2 - Prob. 19.3QC Ch. 19.3 - Prob. 19.4QC Ch. 19.4 - Prob. 19.5QC Ch. 19.5 - Prob. 19.6QC Ch. 19 - Prob. 1P Ch. 19 - Prob. 2P Ch. 19 - Prob. 3P Ch. 19 - Prob. 4P

Solution Summary: The author explains the structure of Ribitol, ß-D-ribose 1-phosphate, and D-Ribo.

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Chapter 19 Solutions