The full name along with the anomeric designation of the following compound should be determined: Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations. A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

Question

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Answer 1

Question

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.

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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

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Answer 2

Question

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.

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Answer 3

Question

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.

Answer 6

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

Answer 7

Chapter 19, Problem 21P

(a)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

Answer 8

(a)

Expert Solution

Answer to Problem 21P

α-D- Galactose.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 2

For a D-sugar, the group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 3

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomericis present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Galactose.

Answer 13

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

Answer 14

(b)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

Answer 15

(b)

Expert Solution

Answer to Problem 21P

α-D- Fructose.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 5

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 6

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Fructose.

Answer 20

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

Answer 21

(c)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

Answer 22

(c)

Expert Solution

Answer to Problem 21P

α-D- Glucose.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 8

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 9

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the opposite side as that of the -CH2OH group, so it is designated as alpha, α .

Hence, the name of compound is α-D- Glucose.

Answer 27

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.

Answer 28

(d)

Interpretation Introduction

Interpretation: The full name along with the anomeric designation of the following compound should be determined:

Concept Introduction: A common way of writing structural formula which represent the cyclic structure of monosaccharides is said to be the Haworth projection, which is best represented by chair conformations.

A convention used to represent a 3-D stereo formula in 2-D representation is said to be Fischer projections. In this projection, the vertical lines represent bonds below the plane of the paper and horizontal lines represents bonds above the plane of the paper.

Answer 29

(d)

Expert Solution

Answer to Problem 21P

β-D- Mannose.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Drawing the Fischer projection of given compound as:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 11

For a D-sugar, the -OH group attached to the bottom chiral carbon is present at the right-hand side whereas for L-sugar it is present at left-hand side.

A new carbon stereocenter created by the conversion of an open structure to a cyclic structure is said to be the anomeric carbon. In carbohydrates, when the hydroxy group on an anomeric carbon is present on the same side as that of the -CH2OH group, then it is designated as beta, β whereas when the hydroxy group on an anomeric carbon is present on the opposite side as that of the -CH2OH group, then it is designated as alpha, α .

The anomeric carbon of the given compound is shown by “*”:

Introduction To General, Organic, And Biochemistry, Chapter 19, Problem 21P , additional homework tip 12

Since, in the given sugar the -OH group in C-5 position is at right-hand side so, the sugar is D-sugar. And the hydroxy group on an anomeric is present on the same side as that of the -CH2OH group, so it is designated as beta, β .

Hence, the name of compound is β-D- Mannose.