Concept explainers
Interpretation:
The mechanism for the epimerization of cis-declone to trans-declone, and the chair conformational structure that show trans-declone is more stable than cis-declone are to be drawn.
Concept introduction:
Keto and enol forms of carbonyl compounds are called constitutional isomers. Interconvertible keto and enol forms are called tautomers.
Racemization takes place at the
Cis–trans isomers are known as configurational isomers. If two groups are present on the same side of the carbon double bond, the isomer is a cis-isomer. If two groups are present on the opposite side of the carbon double bond, the isomer is a trans-isomer.
Epimerization is the process by which less stable epimers are converted to more stable epimers.
Want to see the full answer?
Check out a sample textbook solutionChapter 18 Solutions
Organic Chemistry
- Arrange the alkenes in each set in order of increasing rate of reaction with HI and explain the basis for your ranking. Draw the structural formula of the major product formed in each case.arrow_forwardGive reasons: (i) C—Cl bond length in chlorobenzene is shorter than C—Cl bond length in CH3—Cl.(ii) The dipole moment of chlorobenzene is lower than that of cyclohexyl chloride.(iii) SN1 reactions are accompanied by racemization in optically active alkyl halidesarrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H₂O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data? a. Isomer A is cyclopentene and isomer is 1-pentyne O b. Isomer A is cyclopentene and isomer B is 1-methylcyclobutene c. Isomer A is cyclopentene and isomer B is 3-methylcyclobutene d. Isomer A is 1-methylcyclobutene and isomer B is 3-methylcyclobutenearrow_forward
- Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?arrow_forwardRank the compounds in each group according to their reactivity towardelectrophilic substitution.(a) Chlorobenzene, o-dichlorobenzene, benzene(b) p-Bromonitrobenzene , nitrobenzene, phenol(c) Fluorobenzene, benzaldehyde, a-xylene(d) Benzonitrile, p-methylbenzonitr ile,p-methoxybenzonitrilearrow_forward
- Which of the following could be used as a solvent in the deprotonation reaction of terminal alkynes? A CH;OH (I) B CH;COOH (I) NH3 (1) D) H20 ()arrow_forwardCompound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a Pd/C catalyst. On treatment of A with dilute H2SO4, dehydration occurred and an optically inactive alkene B, C11H14 was produced as the major product. Alkene B, on ozonolysis, gave two products. Product C, C7H6O, was shown to be an aldehyde while product D, C4H8O, was shown to be a ketone. Draw the structure of compound C. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. HELP PLEASE I DONT UNDERSTAND THE PROCESSarrow_forwardCompound F may be synthesised by the method attached: When 2-chloropropane treated with NaOH and 1-chloropropane treated with NaOH separately produce two different functional groups. Provide both reactions and explain the two different functional groups produced.arrow_forward
- Compound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a Pd/C catalyst. On treatment of A with dilute H2SO4, dehydration occurred and an optically inactive alkene B, C11H14 was produced as the major product. Alkene B, on ozonolysis, gave two products. Product C, C8H8O, was shown to be a methyl ketone while product D, C3H6O, was shown to be an aldehyde.arrow_forwardAlkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase C 1. B2H6, diglyme (a) 2. H2O2, HO¯, H2Oarrow_forwardAlkenes can be converted to alcohols by hydroboration-oxidation. (a) Draw the structure of the alcohol or alcohols formed in the reaction sequence. Clearly indicate stereochemistry by drawing a wedged bond, a dashed bond and two in-plane bonds per each chiral carbon. Draw hydrogen atoms that are connected to wedge-and-dash bonds.(b) Characterize the product or products of the reactions. Be sure to draw hydrogens on oxygen, where applicable. Select Draw Rings More Erase H 1. B,H§, diglyme (a) 2. H2O2, HO", H2Oarrow_forward