Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 18, Problem 2PC
Program Plan Intro
Linked List Operations
Program Plan:
“IntList.h”:
- Include the required specifications into the program.
- Define a class named “IntList”.
- Declare the member variables “value” and “*next” in structure named “ListNode”.
- Declare the constructor, destructor, and member functions in the class.
“IntList.cpp”:
- Include the required header files into the program.
- Define a function named “appendNode()” to insert the node at end of the list.
- Declare the structure pointer variables “newNode” and “dataPtr” for the structure named “ListNode”.
- Assign the value “num” to the variable “newNode” and assign null to the variable “newNode”.
- Using “if…else” condition check whether the list is empty or not, if the “head” is empty then make a new node into “head” pointer. Otherwise, make a loop to find last node in the loop.
- Assign the value of “dataPtr” into the variable “newNode”.
- Define a function named “print()” to print the values in the list.
- Declare the structure pointer “dataPtr” for the structure named “ListNode”.
- Initialize the variable “dataPtr” with the “head” pointer.
- Using “if…else” to check whether the list is empty or not, if the list is empty display an appropriate message on the screen.
- Otherwise, make a loop “while” to display the values of the list.
- Define a function named “insertNode()” to insert a value into the list.
- Declare the structure pointer variables “newNode”, “dataPtr”, and “prev” for the structure named “ListNode”.
- Make a “newNode” value into the received variable value “num”.
- Use “if…else” condition to check whether the list is empty or not.
- If the list is empty then initialize “head” pointer with the value of “newNode” variable.
- Otherwise, make a “while” loop to test whether the “num” value is less than the list values or not.
- Use “if…else” condition to initialize the value into list.
- Define a function named “deleteNode()” to delete a value from the list.
- Declare the structure pointer variables “dataPtr”, and “prev” for the structure named “ListNode”.
- Use “if…else” condition to check whether the “head” value is equal to “num” or not.
- Initialize the variable “dataPtr” with the value of the variable “head”.
- Remove the value using “delete” operator and reassign the “head” value into the “dataPtr”.
- If the “num” value not equal to the “head” value, then define the “while” loop to assign the “dataPtr” into “prev”.
- Use “if” condition to delete the “prev” pointer.
- Define the destructor to destroy the list values from the memory.
- Declare the structure pointer variables “dataPtr”, and “nextNode” for the structure named “ListNode”.
- Initialize the variable “dataPtr” with the “head” pointer.
- Define a “while” loop to make the links of node into “nextNode” and remove the node using “delete” operator.
“main.cpp”:
- Include the required header files into the program.
- Declare an object named “obj” for the class “IntList”.
- Make a call to functions for insert, append, and delete operations.
- Make a call to the function “print” to display all the values in the list on the screen.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
C++ function Linked list
Write a function, to be included in an unsorted linked list class, called replaceItem, that will receive two parameters, one called olditem, the other called new item. The function will replace all occurrences of old item with new item (if old item exists !!) and it will return the number of replacements done.
Remove Duplicates
This function will receive a list of elements with duplicate elements, this function should remove the duplicate elements in the list and return a list without duplicate elements. The elements in the returned list must be in the same order that they were found in the list the function received. A duplicate element is an element found more than one time in the specified list.
struct Node {
int data;
Node * next;
};
Node • head;
a. Write a function named addNode that takes in a variable of type int and inserts it at the head of
the list.
b. Write a function named removeNode that removes a node at the head of the list.
Chapter 18 Solutions
Starting Out with C++ from Control Structures to Objects (9th Edition)
Ch. 18.1 - Prob. 18.1CPCh. 18.1 - Prob. 18.2CPCh. 18.1 - Prob. 18.3CPCh. 18.1 - Prob. 18.4CPCh. 18.2 - Prob. 18.5CPCh. 18.2 - Prob. 18.6CPCh. 18.2 - Prob. 18.7CPCh. 18.2 - Prob. 18.8CPCh. 18.2 - Prob. 18.9CPCh. 18.2 - Prob. 18.10CP
Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - Prob. 3RQECh. 18 - Prob. 4RQECh. 18 - Prob. 5RQECh. 18 - Prob. 6RQECh. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 19RQECh. 18 - Prob. 20RQECh. 18 - Prob. 21RQECh. 18 - Prob. 22RQECh. 18 - Prob. 23RQECh. 18 - Prob. 24RQECh. 18 - Prob. 25RQECh. 18 - T F The programmer must know in advance how many...Ch. 18 - T F It is not necessary for each node in a linked...Ch. 18 - Prob. 28RQECh. 18 - Prob. 29RQECh. 18 - Prob. 30RQECh. 18 - Prob. 31RQECh. 18 - Prob. 32RQECh. 18 - Prob. 33RQECh. 18 - Prob. 34RQECh. 18 - Prob. 35RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - List Template Create a list class template based...Ch. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 14PCCh. 18 - Prob. 15PC
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- card_t * moveCardBack (card t *head); The moveCardBack function will take the card in front of the pile and place it in the back. In coding terms, you are taking the head of the linked list and moving it to the end. The function has one parameter which is the head of the linked list. After moving the card to the back, the function returns the new head of the linked list.arrow_forwardC++ Programming Language ::::::: Redo the same functions this time as nonmember functions please : NOTE: You can add only one function into the linked list class get_at_position which will return value of element at given position. 1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}. 2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}. 3)Count common elements : Count common values between two simply linked lists.So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3. 4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not.So if a list contains {1, 3, 7, 8, 9}…arrow_forward@6 The Reference-based Linked Lists: Select all of the following statements that are true. options: As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions. According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node. According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node. In a double-ended singly linked list, the tail reference variable provides access to the entire list. In a circular linked list, the last node references the first node.arrow_forward
- a) Write a function to get the value of the Nu node in a Linked List. [Note: The first (N=1) item in the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return False if the list has fewer than N elements. The Linked List structure supports the following function. def getlead(self): return selt.head # it points to a Node structure The Node structure supports the following functions. def getData(self): return self.data # it returns the value stored in the Node def getNext(self): return self next # it points to the next Node b) Write a function that counts the number of times a given integer occurs in a Linked List. Assume similar structures as defined in 1.arrow_forwardC++ ProgrammingActivity: Deque Linked List Explain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. #include "deque.h" #include "linkedlist.h" #include <iostream> using namespace std; class DLLDeque : public Deque { DoublyLinkedList* list; public: DLLDeque() { list = new DoublyLinkedList(); } void addFirst(int e) { list->addAt(e,1); } void addLast(int e) { list->addAt(e,size()+1); } int removeFirst() { return list->removeAt(1); } int removeLast() { return list->removeAt(size()); } int size(){ return list->size(); } bool isEmpty() { return list->isEmpty(); } // OPTIONAL: a helper method to help you debug void print() {…arrow_forwardReference-based Linked Lists: Select all of the following statements that are true. As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions. According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node. According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node. In a double-ended singly linked list, the tail reference variable provides access to the entire list. In a circular linked list, the last node references the first node.arrow_forward
- Circular linked list is a form of the linked list data structure where all nodes are connected as in a circle, which means there is no NULL at the end. Circular lists are generally used in applications which needs to go around the list repeatedly. struct Node * insertTONull (struct Node *last, int data) // This function is only for empty list 11 5 15 struct Node insertStart (struct Node +last, int data) In this question, you are going to implement the insert functions of a circular linked list in C. The Node struct, print function and the main function with its output is given below: struct Node { int data; struct Node *next; }; struct Node insertEnd (struct Node *last, int data) void print(struct Node *tailNode) struct Node *p; if (tailNode -- NULL) struct Node * insertSubseq (struct Node *last, int data, int item) puts("Empty"); return; p - tailNode → next; do{ printf("%d ",p→data); p - p > next; while(p !- tailNode →next); void main(void) { struct Node *tailNode - NULL; tailNode -…arrow_forwardstruct node{ int a; struct node * nextptr; }; Write two functions. One for inserting new values to a link list that uses the given node structure. void insert(struct node **head, int value); Second function is called to count the number of even numbers in the link list. It returns an integer that represents the number of even numbers. int countEvenNumbers(struct node *head); Write a C program that reads a number of integers from the user and insert those integers into a link list (use insert function). Later pass the head pointer of this link list to a function called countEvenNumbers. This function counts and returns the number of even numbers in the list. The returned value will be printed on the screen. Note 1: Do not modify the function prototypes. Sample Input1: Sample Output1: 45 23 44 12 37 98 33 35 -1 3 Sample Input2: Sample Output2: 11 33 44 21 22 99 123 122 124 77 -1 4arrow_forwardc++ data structures, linked list. write a function that rearrange the linked list of integers such as the odd items comes first don''t use different data structures.arrow_forward
- for c++ please thank you please type the code so i can copy and paste easily thanks. 4, List search Modify the linked listv class you created in the previous programming challange to include a member function named search that returns the position of a specific value, x, in the lined list. the first node in the list is at position 0, the second node is at position 1, and so on. if x is not found on the list, the search should return -1 test the new member function using an approprate driver program. here is my previous programming challange. #include <iostream> using namespace std; struct node { int data; node *next; }; class list { private: node *head,*tail; public: list() { head = NULL; tail = NULL; } ~list() { } void append() { int value; cout<<"Enter the value to append: "; cin>>value; node *temp=new node; node *s; temp->data = value; temp->next = NULL; s = head; if(head==NULL) head=temp; else { while (s->next != NULL) s = s->next; s->next =…arrow_forwardstruct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };arrow_forwardflip_matrix(mat:list)->list You will be given a single parameter a 2D list (A list with lists within it) this will look like a 2D matrix when printed out, see examples below. Your job is to flip the matrix on its horizontal axis. In other words, flip the matrix horizontally so that the bottom is at top and the top is at the bottom. Return the flipped matrix. To print the matrix to the console: print('\n'.join([''.join(['{:4}'.format(item) for item in row]) for row in mat])) Example: Matrix: W R I T X H D R L G L K F M V G I S T C W N M N F Expected: W N M N F G I S T C L K F M V H D R L G W R I T X Matrix: L C S P Expected: S P L C Matrix: A D J A Q H J C I Expected: J C I A Q H A D Jarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
C++ Programming: From Problem Analysis to Program...Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning
C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr
C++ Programming: From Problem Analysis to Program...
Computer Science
ISBN:9781337102087
Author:D. S. Malik
Publisher:Cengage Learning
C++ for Engineers and Scientists
Computer Science
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Course Technology Ptr