Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 18, Problem 2PC
Program Plan Intro
Linked List Operations
Program Plan:
“IntList.h”:
- Include the required specifications into the program.
- Define a class named “IntList”.
- Declare the member variables “value” and “*next” in structure named “ListNode”.
- Declare the constructor, destructor, and member functions in the class.
“IntList.cpp”:
- Include the required header files into the program.
- Define a function named “appendNode()” to insert the node at end of the list.
- Declare the structure pointer variables “newNode” and “dataPtr” for the structure named “ListNode”.
- Assign the value “num” to the variable “newNode” and assign null to the variable “newNode”.
- Using “if…else” condition check whether the list is empty or not, if the “head” is empty then make a new node into “head” pointer. Otherwise, make a loop to find last node in the loop.
- Assign the value of “dataPtr” into the variable “newNode”.
- Define a function named “print()” to print the values in the list.
- Declare the structure pointer “dataPtr” for the structure named “ListNode”.
- Initialize the variable “dataPtr” with the “head” pointer.
- Using “if…else” to check whether the list is empty or not, if the list is empty display an appropriate message on the screen.
- Otherwise, make a loop “while” to display the values of the list.
- Define a function named “insertNode()” to insert a value into the list.
- Declare the structure pointer variables “newNode”, “dataPtr”, and “prev” for the structure named “ListNode”.
- Make a “newNode” value into the received variable value “num”.
- Use “if…else” condition to check whether the list is empty or not.
- If the list is empty then initialize “head” pointer with the value of “newNode” variable.
- Otherwise, make a “while” loop to test whether the “num” value is less than the list values or not.
- Use “if…else” condition to initialize the value into list.
- Define a function named “deleteNode()” to delete a value from the list.
- Declare the structure pointer variables “dataPtr”, and “prev” for the structure named “ListNode”.
- Use “if…else” condition to check whether the “head” value is equal to “num” or not.
- Initialize the variable “dataPtr” with the value of the variable “head”.
- Remove the value using “delete” operator and reassign the “head” value into the “dataPtr”.
- If the “num” value not equal to the “head” value, then define the “while” loop to assign the “dataPtr” into “prev”.
- Use “if” condition to delete the “prev” pointer.
- Define the destructor to destroy the list values from the memory.
- Declare the structure pointer variables “dataPtr”, and “nextNode” for the structure named “ListNode”.
- Initialize the variable “dataPtr” with the “head” pointer.
- Define a “while” loop to make the links of node into “nextNode” and remove the node using “delete” operator.
“main.cpp”:
- Include the required header files into the program.
- Declare an object named “obj” for the class “IntList”.
- Make a call to functions for insert, append, and delete operations.
- Make a call to the function “print” to display all the values in the list on the screen.
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Chapter 18 Solutions
Starting Out with C++ from Control Structures to Objects (9th Edition)
Ch. 18.1 - Prob. 18.1CPCh. 18.1 - Prob. 18.2CPCh. 18.1 - Prob. 18.3CPCh. 18.1 - Prob. 18.4CPCh. 18.2 - Prob. 18.5CPCh. 18.2 - Prob. 18.6CPCh. 18.2 - Prob. 18.7CPCh. 18.2 - Prob. 18.8CPCh. 18.2 - Prob. 18.9CPCh. 18.2 - Prob. 18.10CP
Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - Prob. 3RQECh. 18 - Prob. 4RQECh. 18 - Prob. 5RQECh. 18 - Prob. 6RQECh. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 19RQECh. 18 - Prob. 20RQECh. 18 - Prob. 21RQECh. 18 - Prob. 22RQECh. 18 - Prob. 23RQECh. 18 - Prob. 24RQECh. 18 - Prob. 25RQECh. 18 - T F The programmer must know in advance how many...Ch. 18 - T F It is not necessary for each node in a linked...Ch. 18 - Prob. 28RQECh. 18 - Prob. 29RQECh. 18 - Prob. 30RQECh. 18 - Prob. 31RQECh. 18 - Prob. 32RQECh. 18 - Prob. 33RQECh. 18 - Prob. 34RQECh. 18 - Prob. 35RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - List Template Create a list class template based...Ch. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 14PCCh. 18 - Prob. 15PC
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