
Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 1, Problem 1RQE
Explanation of Solution
Difference between main memory and secondary storage:
Main Memory | Secondary storage |
In Main memory or Random Access Memory (RAM), the data is directly accessed by the processing unit. | In secondary storage, the data is transferred to the main memory and then routed to the processing unit. |
Main memory is volatile, which means the information stored in the memory would be erased when the computer is turned off. | Secondary storage is non-volatile, which means the information stored in the memory is not erased when the computer is turned off. |
Main memory has a limited storage capacity. | Secondary storage can store bulk amount of data in a single unit. |
Main memory devices are more expensive when compared to the secondary storage devices. | Secondary storage devices are less expensive when compared to the main memory devices. |
The examples of main memory are,
|
The examples of secondary storage are,
|
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I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
Chapter 1 Solutions
Starting Out with C++ from Control Structures to Objects (9th Edition)
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