Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 18, Problem 20P
Substantial fractions of the genomes of many plants consist of segmental duplications; for example, approximately
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When the S.cerevisiae genome was sequenced and surveyed for possible genes, only about 40% of those genes had been previously identified in forward genetic screens. This left about 60% of predcited genes with no known function, leading some to dub the genes fun (function unknown) genes.
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Although DNA transposons are abundant in the genomes of multicellular eukaryotes, class 1 elements usually make up the largest fraction of very large genomes such as those from humans (~2500 Mb), maize (~2500 Mb), and barley (~5000 Mb). Given what you know about class 1 and class 2 elements, what is it about their distinct mechanisms of transposition that would account for this consistent difference in abundance?
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Chapter 18 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 18 - You have discovered a new species of Archaea from...Ch. 18 - 16.2 Repetitive DNA poses problems for genome...Ch. 18 - 16.3 When the whole-genome shotgun sequence of the...Ch. 18 - How do cDNA sequences facilitate gene annotation?...Ch. 18 - 16.5 How do comparisons between genomes of related...Ch. 18 - 16.6 You are designing algorithms for the...Ch. 18 - 16.7 You have sequenced a region of the Bacillus...Ch. 18 - You have just obtained 100-kb of genomic sequence...Ch. 18 - 16.9 The human genome contains a large number of...Ch. 18 - Based on the tree of life in Figure 16.12, would...
Ch. 18 - 16.11 When comparing genes from two sequenced...Ch. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Prob. 14PCh. 18 - 16.16 Consider the phylogenetic tree below with...Ch. 18 - You have isolated a gene that is important for the...Ch. 18 - 16.18 When the human genome is examined, the...Ch. 18 - Symbiodinium minutum is a dinoflagellate with a...Ch. 18 - Substantial fractions of the genomes of many...Ch. 18 - 16.21 A modification of the system, called the ...Ch. 18 - 16.22 A substantial fraction of almost every...Ch. 18 - 16.23 In the globin gene family shown in Figure ,...Ch. 18 - You are studying similarities and differences in...Ch. 18 - In conducting the study described in Problem 24,...Ch. 18 - Prob. 26PCh. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - If you were to compare your genome sequence with...
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- Not all inherited traits are determined by nuclear genes (i.e., genes located in the cell nucleus) that are expressed during the life of an individual. In particular, maternal effect genes and mitochondrial DNA are notable exceptions. With these ideas in mind, let’s consider the cloning of a sheep (e.g., Dolly). A. With regard to maternal effect genes, is the phenotype of such a cloned animal determined by the animal that donated the enucleatedegg or by the animal that donated the somatic cell nucleus? Explain.arrow_forwardTraditional gene mapping has been applied successfully to a variety of organisms including yeast, fungi, maize, and Drosophila. However, human gene mapping has only recently shared a similar spotlight. What factors have delayed the application of traditional gene-mapping techniques in humans?arrow_forwardThe fruit fly Drosophila melanogaster has about 2 x 10^8 base pairs of DNA per haploid genome, of which about 75% in nonrepeated DNA. The DNA is distributed among four pairs of homologous chromosomes, which have a total of about 5,000 visible bands when in polytene forms in the salivary gland. The number of genes initially estimated from mutational studies was also about 5,000 but recent DNA sequencing studies suggest that the gene number may be somewhat higher. a. Why was it tempting to speculate that each band corresponds to a single gene? What does this suggest about the number of different proteins Drosophila can make? Does that seem like a reasonable number to you? b. Assuming all the nonrepeated DNA is uniformly distributed in the chromosomes, how much nonrepeated DNA (in base pairs) is there in average band?arrow_forward
- A paper hypothesizes that white flowers are unable to produce anthocyanins (purple pigments) because they lack a functional “A” protein. However, it is also possible that an unknown gene is responsible for the lack of anthocyanins. Now that they have isolated DNA sequences of the “A” allele, design an experiment to use these DNA sequences to distinguish between these two hypotheses.arrow_forwardIf you wanted to analyze the size and abundance of the HOAP protein in an extract from a Drosophila animal that you think may be mutant for the HOAP gene, what method could you use to target your analysis specifically to the HOAP protein in that extract?arrow_forwardIn contrast with the genomic manipulations of animals and plants described in this chapter, human genetherapy is directed specifically at altering the genomes of somatic cells rather than germ-line cells.Why couldn’t or wouldn’t medical scientists try to alter the genome of human germ-line cells?arrow_forward
- APOE gene has been found to be a major contributor to sporadic Alzheimer's disease (AD), by acting as an age-of-onset modifier for the common relatively late-onset forms of the disease. Among four alleles causing early onset of AD, the epsilon4 allele (APOE4) disrupts this function. If you generate transgenic monkeys in which the normal allele of APOE gene is knocked out, what phenotype will you expect for those knockout monkeys? A. The APE mRNA expression will be completely suppressed. B. They slow down the development of AD. C. They develop AD early. D. They don't show any AD symptom.arrow_forwardIn DNA-hybridization experiments on six species of plants in the genus Vicia, DNA was isolated from each of the six species, denatured by heating, and sheared into small fragments (W. Y. Chooi. 1971. Genetics 68:213–230). In one experiment, DNA from each species and from E. coli was allowed to renature. The graph shows the results of this renaturation experiment. Q. Notice that, for the Vicia species, the rate of renaturation is much faster in the first hour and then slows down. What might cause this initial rapid renaturation and the subsequent slowdown?arrow_forwardLeber Congenital Amaurosis (LCA) causes progressive vision loss due to defects in the gene that encodes RPE65 isomerase. Affected individuals are homozygous recessive for mutant alleles of the RPE65 gene. You are trying to determine the molecular nature of the mutations in three individuals with LCA. For ease of analysis, you may assume that each individual is homozygous for the same mutant allele (though the three individuals have different mutations than each other). You use the polymerase chain reaction to amplify DNA from each patient and you determine the sequence of the DNA and compare it to unaffected individuals. You identify the following differences. Note that the non-template strand of DNA is given and the changes are highlighted using red boldface. You can assume that the sequences are in the first reading frame (eg. the first three nucleotides of each sequence is a codon). The coding region of the gene is 1602 bp and the position of the sequences shown below is…arrow_forward
- Forward Genetics Analysis uses a variety of beneficial approaches to identify never before described genes. For each of the following approaches or outcomes, briefly (maximum 2 sentences) discuss in your own words, their purpose in Forward Genetics Analysis. c) Mendelian ratios d) Genetic screenarrow_forwardOur understanding of maternal effect genes has been greatly aided by their identification in experimental organisms such as Drosophila melanogaster and Caenorhabditis elegans. In experimental organisms with a short generation time, geneticists have successfully searched for mutant alleles that prevent the normal process of embryonic development. In many cases, the offspring die at early embryonic or larval stages. These are called maternal effect lethal alleles. How would a researcher identify a mutation that produced a recessive maternal effect lethal allele?arrow_forwardNext-generation sequencing reveals that six new mutations have occurred in the coding regions of genes in an individual diploid fly. If the coding regions of this fly comprise 100 million nucleotides per haploid genome, what is the mutation rate per nucleotide?arrow_forward
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