Chapter 1.8, Problem 16PPS

To determine

To Sketch: The graph which is linear and $x$ Interceptat $-2$ , positive for $x<-2$ and negative for $x>-2$

Answer to Problem 16PPS

  

Explanation of Solution

Given: To sketch the graph with the following characteristics

The graph which is linear and $x$ Intercept at $-2$ and positive for $x<-2$ and negative for $x>-2$

Given: $x$ Intercept is $-2$

Since the graph has $x$ Intercept= $-2$ , it must cross the $x$ axis at $-2$ . The graph must be positive for $x<-2$ so it must be above the $x$ axis for the values that are less than $-2$ and below the $x$ axis for the values that are greater than $-2$ because the graph is negative for $x>-2$