Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
10th Edition
ISBN: 9780134673301
Author: Waits, Foley, Kennedy, Bock Demana
Publisher: PEARSON
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Expert Solution & Answer
Chapter 1.7, Problem 51E
Solution
(a)
To find: The scatter graph of given data.
The graph is given
Given information:
| Time(min) | Temperature | Time (L2) | Temperature |
| 1 | 184.3 | 11 | 140 |
| 2 | 178.5 | 12 | 136.1 |
| 3 | 173.5 | 13 | 133.5 |
| 4 | 168.6 | 14 | 130.5 |
| 5 | 164.0 | 15 | 127.9 |
| 6 | 159.2 | 16 | 125 |
| 7 | 155.1 | 17 | 122.8 |
| 8 | 151.8 | 18 | 119.9 |
| 9 | 147 | 19 | 117.2 |
| 10 | 143.7 | 20 | 115.2 |
Graph of time from L1 and temperature from L2 is given below.
(b)
To find: Store L2-72 and find L3.
The table is given
Given information:
| L3 Time | temperature |
| 21 | 68 |
| 22 | 64.1 |
| 23 | 61.5 |
| 24 | 68.5 |
| 25 | 55.9 |
| 26 | 53 |
| 27 | 50.8 |
| 28 | 47.9 |
| 29 | 45.2 |
| 30 | 43.2 |
(c)
To find: Find the exponential regression for L3.
The exponential regression for L3 is y=73.71⋅(0.9485)x
Given information:
| L3 Time | temperature |
| 21 | 68 |
| 22 | 64.1 |
| 23 | 61.5 |
| 24 | 68.5 |
| 25 | 55.9 |
| 26 | 53 |
| 27 | 50.8 |
| 28 | 47.9 |
| 29 | 45.2 |
| 30 | 43.2 |
The curve to be fitted is y=abx taking logarithm on both sides, we get
log10(y)=log10(a)+xlog10(b)
y=a+bx where Y=log10(y), A=log10(a),B=log10(b)
which linear in Y,x
So the corresponding normal equations are
∑Y=nA+B∑x
∑xY=A∑x+B∑x2
The values are calculated using the following table
| x | y | Y=log10(y) | x2 | x·Y |
| 1 | 68 | 1.8325 | 1 | 1.8325 |
| 2 | 64.1 | 1.8069 | 4 | 3.6137 |
| 3 | 61.5 | 1.7889 | 9 | 5.3666 |
| 4 | 68.5 | 1.8357 | 16 | 7.3428 |
| 5 | 55.9 | 1.7474 | 25 | 8.7371 |
| 6 | 53 | 1.7243 | 36 | 10.3457 |
| 7 | 50.8 | 1.7059 | 49 | 11.941 |
| 8 | 47.9 | 1.6803 | 64 | 13.4427 |
| 9 | 45.2 | 1.6551 | 81 | 14.8962 |
| 10 | 43.2 | 1.6355 | 100 | 16.3548 |
| --- | --- | --- | --- | --- |
| ∑x=55 | ∑y=558.1 | ∑Y=17.4124 | ∑x2=385 | ∑x· Y=93.8731 |
Substituting these values in the normal equations
10A+55B=17.4124
55A+385B=93.8731
Use elimination method we obtain A=1.8676,B=-0.023
∴a=antilog10(A)=antilog10(1.8676)=73.7191 and b=antilog10(B)=antilog10(-0.023)=0.9485
Now substituting this values in the equation is y=abx , we get y=73.71⋅(0.9485)x
Chapter 1 Solutions
Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
Ch. 1.1 - Prob. 1QRCh. 1.1 - Prob. 2QRCh. 1.1 - Prob. 3QRCh. 1.1 - Prob. 4QRCh. 1.1 - Prob. 5QRCh. 1.1 - Prob. 6QRCh. 1.1 - Prob. 7QRCh. 1.1 - Prob. 8QRCh. 1.1 - Prob. 9QRCh. 1.1 - Prob. 10QR
Ch. 1.1 - Prob. 1ECh. 1.1 - Prob. 2ECh. 1.1 - Prob. 3ECh. 1.1 - Prob. 4ECh. 1.1 - Prob. 5ECh. 1.1 - Prob. 6ECh. 1.1 - Prob. 7ECh. 1.1 - Prob. 8ECh. 1.1 - Prob. 9ECh. 1.1 - Prob. 10ECh. 1.1 - Prob. 11ECh. 1.1 - Prob. 12ECh. 1.1 - Prob. 13ECh. 1.1 - Prob. 14ECh. 1.1 - Prob. 15ECh. 1.1 - Prob. 16ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.1 - Prob. 45ECh. 1.1 - Prob. 46ECh. 1.1 - Prob. 47ECh. 1.1 - Prob. 48ECh. 1.1 - Prob. 49ECh. 1.1 - Prob. 50ECh. 1.1 - Prob. 51ECh. 1.1 - Prob. 52ECh. 1.1 - Prob. 53ECh. 1.1 - Prob. 54ECh. 1.1 - 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In Exercises 110, evaluate the expression without...Ch. 1.3 - In Exercises 110, evaluate the expression without...Ch. 1.3 - Prob. 4QRCh. 1.3 - In Exercises 110, evaluate the expression without...Ch. 1.3 - Prob. 6QRCh. 1.3 - Prob. 7QRCh. 1.3 - Prob. 8QRCh. 1.3 - Prob. 9QRCh. 1.3 - Prob. 10QRCh. 1.3 - Prob. 1ECh. 1.3 - Prob. 2ECh. 1.3 - In Exercises 112, each graph is a slight variation...Ch. 1.3 - Prob. 4ECh. 1.3 - Prob. 5ECh. 1.3 - Prob. 6ECh. 1.3 - Prob. 7ECh. 1.3 - Prob. 8ECh. 1.3 - Prob. 9ECh. 1.3 - Prob. 10ECh. 1.3 - Prob. 11ECh. 1.3 - Prob. 12ECh. 1.3 - Prob. 13ECh. 1.3 - Prob. 14ECh. 1.3 - Prob. 15ECh. 1.3 - Prob. 16ECh. 1.3 - Prob. 17ECh. 1.3 - Prob. 18ECh. 1.3 - Prob. 19ECh. 1.3 - Prob. 20ECh. 1.3 - Prob. 21ECh. 1.3 - Prob. 22ECh. 1.3 - Prob. 23ECh. 1.3 - Prob. 24ECh. 1.3 - Prob. 25ECh. 1.3 - Prob. 26ECh. 1.3 - Prob. 27ECh. 1.3 - Prob. 28ECh. 1.3 - Prob. 29ECh. 1.3 - Prob. 30ECh. 1.3 - Prob. 31ECh. 1.3 - Prob. 32ECh. 1.3 - Prob. 33ECh. 1.3 - Prob. 34ECh. 1.3 - Prob. 35ECh. 1.3 - 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Prob. 7ECh. 1.4 - Prob. 8ECh. 1.4 - Prob. 9ECh. 1.4 - Prob. 10ECh. 1.4 - Prob. 11ECh. 1.4 - Prob. 12ECh. 1.4 - Prob. 13ECh. 1.4 - Prob. 14ECh. 1.4 - Prob. 15ECh. 1.4 - Prob. 16ECh. 1.4 - Prob. 17ECh. 1.4 - Prob. 18ECh. 1.4 - Prob. 19ECh. 1.4 - Prob. 20ECh. 1.4 - Prob. 21ECh. 1.4 - Prob. 22ECh. 1.4 - Prob. 23ECh. 1.4 - Prob. 24ECh. 1.4 - Prob. 25ECh. 1.4 - Prob. 26ECh. 1.4 - Prob. 27ECh. 1.4 - Prob. 28ECh. 1.4 - Prob. 29ECh. 1.4 - Prob. 30ECh. 1.4 - Prob. 31ECh. 1.4 - Prob. 32ECh. 1.4 - Prob. 33ECh. 1.4 - Prob. 34ECh. 1.4 - Prob. 35ECh. 1.4 - Prob. 36ECh. 1.4 - Prob. 37ECh. 1.4 - Prob. 38ECh. 1.4 - Prob. 39ECh. 1.4 - Prob. 40ECh. 1.4 - Prob. 41ECh. 1.4 - Prob. 42ECh. 1.4 - Prob. 43ECh. 1.4 - Prob. 44ECh. 1.4 - Prob. 45ECh. 1.4 - Prob. 46ECh. 1.4 - Prob. 47ECh. 1.4 - Prob. 48ECh. 1.4 - Prob. 49ECh. 1.4 - Prob. 50ECh. 1.4 - Prob. 51ECh. 1.4 - Prob. 52ECh. 1.4 - Prob. 53ECh. 1.4 - Prob. 54ECh. 1.4 - Prob. 55ECh. 1.5 - Prob. 1QRCh. 1.5 - Prob. 2QRCh. 1.5 - Prob. 3QRCh. 1.5 - Prob. 4QRCh. 1.5 - Prob. 5QRCh. 1.5 - Prob. 6QRCh. 1.5 - Prob. 7QRCh. 1.5 - Prob. 8QRCh. 1.5 - Prob. 9QRCh. 1.5 - Prob. 10QRCh. 1.5 - Prob. 1ECh. 1.5 - Prob. 2ECh. 1.5 - Prob. 3ECh. 1.5 - Prob. 4ECh. 1.5 - Prob. 5ECh. 1.5 - Prob. 6ECh. 1.5 - Prob. 7ECh. 1.5 - Prob. 8ECh. 1.5 - Prob. 9ECh. 1.5 - Prob. 10ECh. 1.5 - Prob. 11ECh. 1.5 - Prob. 12ECh. 1.5 - Prob. 13ECh. 1.5 - In Exercises 1322, find a formula for f1x . 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Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. Freeman
Calculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Introduction to experimental design and analysis of variance (ANOVA); Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=vSFo1MwLoxU;License: Standard YouTube License, CC-BY