Chapter 1.7, Problem 21E

Solution

Find the two numbers.

  $x=496$

  $y=124$

Given:

One positive number is 4 times another positive number. The sum of the two numbers is 620.

Concept Used:

An addition equation shows the sum of two numbers using + and = signs. The equals sign (=) means the things to its left are equal to the things to its right. The plus sign (+) shows you what things to add.

Calculation:

Let one positive number = x

Let second positive number = y

According to question −

  $x=4y$

  $x+y=620$

  $\begin{array}{c}x+y=620\\ asx=4y\\ 4y+y=620\\ 5y=620\\ y=\frac{620}{5}\\ y=124\\ sox=4y\\ x=4(124)\\ x=496\end{array}$

So the two numbers are $x=496$ and $y=124$