The functional groups present in lidocaine has to be identified. Also the structure of carboxylic acid and amine that are needed to form lidocaine has to be drawn. Concept Introduction: Carboxylic acid: One − O H group is attached to the carbonyl carbon atom of the compound. It is represented as R C O O H Amide: One − N H 2 , − N H R ' or − N R ' 2 group is attached to the carbonyl carbon atom of the compound. It is represented as R C O N R ' 2 . Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia. Primary amide is produce when a carboxylic acid reacts with ammonia. Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively. Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine Amines are the derivatives of ammonia ( N H 3 ) with one or more of the hydrogens replaced with a substituent such as an alkyl group. Depending on the number of carbon side chain of the nitrogen, different types of amines can form. Aromatic Compounds: Compounds that are planar, cyclic and having ( 4 n + 2 ) π electrons are known as aromatic compounds.

Question

The preferred substrate is T because the enzyme half-saturates at 7.00 mM for T, but requires 28.0 mM for U, and 112 mM for S. b Question Content Area The rate constant k 2 with substrate S is 9.60×107 sec-1, with substrate T, k 2 = 6.00×104 sec-1, and with substrate U, k 2 = 2.40×106 sec-1. Calculate the catalytic efficiency with S, T, and U. Catalytic efficiency with S = Catalytic efficiency with T = Catalytic efficiency with U = Does enzyme A use substrate S, substrate T, or substrate U with greater catalytic efficiency?

Answer 1

Question

Chapter 17, Problem 17.63AP

Interpretation Introduction

Interpretation:

The functional groups present in lidocaine has to be identified. Also the structure of carboxylic acid and amine that are needed to form lidocaine has to be drawn.

Concept Introduction:

Carboxylic acid: One −OH group is attached to the carbonyl carbon atom of the compound. It is represented as RCOOH

Amide: One −NH2, −NHR' or −NR'2 group is attached to the carbonyl carbon atom of the compound. It is represented as RCONR'2.

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Primary amide is produce when a carboxylic acid reacts with ammonia.

Secondary and tertiary amide is produce when a carboxylic acid reacts with primary and secondary amine respectively.

Ammonium salt is formed when tertiary amine and a carboxylic acid reacts forming an ionic compound with a carboxylate acid anion and a trialkyl ammonium cation since there is no hydrogen atom in trialkyl amine

Amines are the derivatives of ammonia (NH3) with one or more of the hydrogens replaced with a substituent such as an alkyl group.

Depending on the number of carbon side chain of the nitrogen, different types of amines can form.

Aromatic Compounds: Compounds that are planar, cyclic and having (4n+2)π electrons are known as aromatic compounds.

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