Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 17, Problem 17.59E
Interpretation Introduction

Interpretation:

The reason as to why hexanal and 1-hexanol are liquids at room temperature but glucose is solid is to be stated.

Concept introduction:

Carbohydrates are one of the essential macronutrients in our diet. It is the major source of energy and is important for balanced diet. Monosaccharides are the sub-category of carbohydrates that are small units of simple sugars. Glucose is a monosaccharide. The formula for glucose is C6H12O6.

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(b) Glucose has the following structure. Describe the properties based on the structure of glucose.
Draw structures for the straight-chain and ring forms of glucose
How many chiral center, if any, would be formed in this structure?

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Chemistry for Today: General, Organic, and Biochemistry

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