Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 17, Problem 17.53E
Interpretation Introduction

Interpretation:

The following structural characteristics are to be matched with their respective polysaccharide.

a. Contains both α(14) and α(16) glycosidic linkages

b. is composed of glucose monosaccharide units

c. Contains acetal linkages between monosaccharide units

d. is composed of highly branched molecular chains

e. is composed of unbranched molecular chains

f. Contains only α(14) glycosidic linkages

g. Contains only β(14) glycosidic linkages

Concept introduction:

A large molecule formed by combining the multiple numbers of monosaccharides is called polysaccharide. These monosaccharides can be same, known as homo-polysaccharide, or different, known as hetero-polysaccharides. A molecule with a straight chain is called linear polysaccharide and that with a branched chain is called a branched polysaccharide.

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Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions ΔΗ is (pick one) A This reaction is faster above 103. °C than below. AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous only above -9. °C. AS is (pick one) ΔΗ is (pick one) C The reverse of this reaction is always spontaneous. AS is (pick one) 18 Ar

Chapter 17 Solutions

Chemistry for Today: General, Organic, and Biochemistry

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